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PtichkaEL [24]
2 years ago
14

(a) For the accompanying data set, draw a scatter diagram of the data.

Mathematics
1 answer:
lidiya [134]2 years ago
4 0

Answer:

a) n=5 \sum x = 30, \sum y = 25, \sum xy = 162, \sum x^2 =206, \sum y^2 =155  

r=\frac{5(162)-(30)(25)}{\sqrt{[5(206) -(30)^2][5(155) -(25)^2]}}=0.42967  

So then the correlation coefficient would be r =0.430 rounded

b) Null hypothesis: \rho =0

Alternative hypothesis: \rho \neq 0  

Because the correlation coeffcient is positive and the absolute value of the correlation coefficient 0.430 is not greater than the critical value for this dataset, no linear relation exists between x and y.

And the reason is because we fail to reject the null hypothesis.

Step-by-step explanation:

Part a

We have the following data:

x: 2  6  6  7  9

y: 3  2  6  9  5

The correlation coefficient is a "statistical measure that calculates the strength of the relationship between the relative movements of two variables". It's denoted by r and its always between -1 and 1.

And in order to calculate the correlation coefficient we can use this formula:  

r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}  

For our case we have this:

n=5 \sum x = 30, \sum y = 25, \sum xy = 162, \sum x^2 =206, \sum y^2 =155  

r=\frac{5(162)-(30)(25)}{\sqrt{[5(206) -(30)^2][5(155) -(25)^2]}}=0.42967  

So then the correlation coefficient would be r =0.430 rounded

Part b

In order to test the hypothesis if the correlation coefficient it's significant we have the following hypothesis:

Null hypothesis: \rho =0

Alternative hypothesis: \rho \neq 0

The statistic to check the hypothesis is given by:

t=\frac{r \sqrt{n-2}}{\sqrt{1-r^2}}

And is distributed with n-2 degreed of freedom. df=n-2=5-2=3

In our case the value for the statistic would be:

t=\frac{0.430\sqrt{5-2}}{\sqrt{1-(0.430)^2}}=0.825

The critical value for n =5 is given by the table attached. We can see that the critical value is r_{crit}= 0.878, and then the final conclusion would be:

Because the correlation coeffcient is positive and the absolute value of the correlation coefficient 0.430 is not greater than the critical value for this dataset, no linear relation exists between x and y

And the reason is because we fail to reject the null hypothesis.

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Step-by-step explanation:

Remark

Anything multiplied by 0 = 0. So the whole right side is 0.

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Can someone help me with this? please<br><br>alguien me puede ayudar con esto? porfavorr
soldi70 [24.7K]

See attachment for the number line that compares the numbers 5.3, 5 1/5 and 5

<h3>How to plot the numbers on the number line?</h3>

The numbers are given as:

5.3, 5 1/5 and 5

We start by representing the numbers as decimals (i.e. real numbers).

So, we have:

5.3, 5.2 and 5

Reorder the numbers in ascending number (i.e. from least to greatest)

So, we have

5, 5.2 and 5.3

Next, we plot the numbers on a number line using a scale of 0.1

This can be visualized as

5        5.2      5.3

See attachment for the number line that compares the numbers 5.3, 5 1/5 and 5

Read more about number line at

brainly.com/question/24644930

#SPJ1

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