*see attachment below for the dot plots that completes the question.
Answer:
B. Centers: The sea turtles have a greater median age than the koi.
D. Spreads: The ages of the koi are more spread out.
Step-by-step explanation:
The measure of center that can be used for comparison is the median, while the spread can simply be visualised by mere looking at how spread out the dots on the number line are. The spread of both can also be compared using their range. The greater the range, the more spread a data is.
=>Median Differences:
The median age for turtle = the middle value = 55
The median age for koi = 30
Therefore, sea turtles have a greater median age than the koi.
=>Spread Differences:
Range for turtle = the highest age - the least age represented on the dot plot = 65 - 45 = 20
Range for koi = 55 - 10 = 45
Koi has a greater range value than koi. Therefore, the ages of the koi are more spread out.
Answer:
32°
Step-by-step explanation:
Given:
∠DMQ = 58º
In this circle, the radius is DM. Since AD is tangent to the circle M, at point D, and the angle between a tangent and a radius is 90°
Therefore, ∠MDQ = 90°
The total angle in a triangle is 180°. Since we have the values of ∠MDQ and ∠DMQ, ∠DQM will be calculated as:
180 = ∠DMQ + ∠MDQ + ∠DQM
Solving for ∠DQM, we have:
∠DQM = 180 - ∠DMQ - ∠MDQ
∠DQM = 180 - 90 - 58
∠DQM = 32°
The measure of ∠DQM is 32°
