Answer: our function is:
f(x) = A*sin(2*pi*270s*x)
Step-by-step explanation:
We have that the frequency of a given engine is 270 hz, it starts at 0, so we may represent this with a sin function (because sin(0) = 0)
Then we could use the function
f(x) = A*sin(c*x)
A is the maximum intensity of the hum, and c depends on te frequency, we know that the period of a sin function is 2pi, then:
f = 270/s
T = 1/270s
c*1/270s = 2pi
c = 2*pi*270s
Then our function is:
f(x) = A*sin(2*pi*270s*x)
Answer:
a4 = 128
a5 = -512
Step-by-step explanation:
a1= -2
q= (-1)^(n+1) × 4
a4 = a1q³ = (-2) (-4)³ = -2 × -64 = +128
a5 = a1q⁴ = (-2) (-4)⁴ = -2 × 256 = -512
Answer: The correct answer is option C: Both events are equally likely to occur
Step-by-step explanation: For the first experiment, Corrine has a six-sided die, which means there is a total of six possible outcomes altogether. In her experiment, Corrine rolls a number greater than three. The number of events that satisfies this condition in her experiment are the numbers four, five and six (that is, 3 events). Hence the probability can be calculated as follows;
P(>3) = Number of required outcomes/Number of possible outcomes
P(>3) = 3/6
P(>3) = 1/2 or 0.5
Therefore the probability of rolling a number greater than three is 0.5 or 50%.
For the second experiment, Pablo notes heads on the first flip of a coin and then tails on the second flip. for a coin there are two outcomes in total, so the probability of the coin landing on a head is equal to the probability of the coin landing on a tail. Hence the probability can be calculated as follows;
P(Head) = Number of required outcomes/Number of all possible outcomes
P(Head) = 1/2
P(Head) = 0.5
Therefore the probability of landing on a head is 0.5 or 50%. (Note that the probability of landing on a tail is equally 0.5 or 50%)
From these results we can conclude that in both experiments , both events are equally likely to occur.
25/250 = 1/10
I do not know that much english. I an spanish so I might have done it wrong.
