The digit in the hundred thousands place is the 2
Answer:
4(x-7)^2-(x-7)+3 (Assuming t is f)
Step-by-step explanation:
Let s(x)=x-7 and t(x)=4x^2-x+3 .
(t o s)(x)=t(s(x))=t(x-7)
Before I continue this means replace the orginal x in t with x-7.
This will then give you
4(x-7)^2-(x-7)+3
5×21/-1+9
105/-1 +9
-105 +9
-96
hope that helps
Roots: - √5 , √5, and - 3
=> these are factors of the polynomial: (x + √5), (x - √5), and (x + 3).
Multiply those three factors:
(x + √5) (x - √5) ( x + 3) = [x^2 - 5] ( x + 3 ) = x^2 + 3x^2 - 5x - 15
Therefore the polynomial x^2 + 3x^2 - 5x - 15 is a polynomial with the given roots.
Answer: option B. x^3 + 3x^2 - 5x - 15
