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3 years ago

What is the solutions of the equation 2 (x+2) ^2-4=28

Mathematics

1 answer:

JulsSmile [24]3 years ago

3 0

Answer:

x = 2 x = -6

Step-by-step explanation:

2 (x+2) ^2-4=28

Add 4 to each side

2 (x+2) ^2-4+4=28+4

2 (x+2) ^2= 32

Divide by 2

2/2 (x+2) ^2=32/2

(x+2)^2 = 16

Take the square root of each side

sqrt((x+2)^2) =±sqrt( 16)

x+2 = ±4

Subtract 2 from each side

x+2-2 = -2±4

x = -2±4

x = -2+4 and x = -2-4

x = 2 x = -6

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