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scoray [572]
3 years ago
7

s="latex-formula">

please somebody answer
Mathematics
2 answers:
GrogVix [38]3 years ago
8 0

Take the root of both sides of the equation.
y = ^3 √64
Calculate the root.
y = 4

In the end, when you substitute y for 4,
4^3 will get you 64.
jeka943 years ago
5 0
The answer to your question is: Y=4
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explain why x and 4x -10 are factors of the expression x(4x-10)^ rather than terms of the expression . what are the terms of the
Lubov Fominskaja [6]
X(4x-10)^

you can write

a(b)^ 

where
a = x
and b = (4x-10)

so a*b  have two factors a and b

b has also power = so b^    so it is means b*b*b*b*.....  so b^ have always factor b

(4x-10) 

4x < 10
x<10/4 
x < 2.5







5 0
4 years ago
Find the nth term of the sequence 25 40 55 70 85
PilotLPTM [1.2K]
Nth term = 25 + 15 x(n-1)
3 0
3 years ago
the area of a right triangle is 336 square centimeters. The base of the right triangle is 48 centimeters. What is the length of
Alex73 [517]

Answer:

50 cm

Step-by-step explanation:

So the first step is to find the height, and to do that you know that the area of a triangle is height * base / 2 =  area. Plugging in the numbers you have, you get:

height*48/2=336

Then, this becomes

height * 24 = 336

Divide both sides by 24

height = 14

Now you can use the base and the height to find the hypotenuse using the Pythagorean Theorem: a^{2} +b^{2} =c^{2}

48^{2} +14^{2} =c^{2} \\2304 + 196 = c^{2}\\2500 = c^2\\50 = c\\c = 50

Therefore the length of the hypotenuse is 50 cm

8 0
3 years ago
Area = 300 square feet
m_a_m_a [10]

Answer:

Length=24.32 feet

width=12.32 feet

Step-by-step explanation:

Let x be the width of a rectangle

Let l be the length of a rectangle

Let A be the area of rectangle

Given.

Length must be 12 feet longer than width

therefore

Length=12+w

l=12+w

Area of rectangle

A=300

We know that area of rectangle is

A=l\times w---------------------(1)

put all known values in equation 1

300=(12+x)\times x

x^{2} +12x=300\\x^{2} +12x-300=0

Find roots by this formula

=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}

=\frac{-12\pm\sqrt{12^{2}-4(1)(-300)}}{2(1)}

=\frac{-12\pm\sqrt{1344}}{2}

x=-6+4\sqrt{21} \\x=-6-4\sqrt{21}

x=12.32\\x=-24.32

check both value in equation 1

for x=12.32

A=(12+12.32)\times 12.32

A=299.62

x=12.32 is satisfy the equation

So The length of rectangle l=12+12.32=24.32 feet

And width is 12.32 feet

3 0
4 years ago
- 4j - 1 - 4j+6<br><br> Write that expression in the simplest form
Anika [276]

Answer:

-8j+5

Step-by-step explanation:

the answer is -8j+5

4 0
3 years ago
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