This reduced fraction would be c. x+y/8.
You can apply the Difference of Two Squares Formula (x^2+y^2)=(x+y)(x-y). Then, you can factor out the common term 8 and cancel out the common factor x-y. Hope this helps! :)
1/1+z+4/z+z^2 +1
1/2z =4/2z^2 +1
1/2z=2(z^2+2)/2z^2
1/2z=z^4+2z^2
z^5/2+2z^2
=therefore it has no solution I think this is the stes i m not sure sorry i m not sure ,try asking somebody else to cuz i m not sure
