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Mrac [35]
3 years ago
6

The following 5 keys are for the following 5 locked padlocks. Each key opens one and only one padlock. Different keys open diffe

rent padlocks. What is the least number of trials needed to guarantee that you will open all 5 padlocks?
Mathematics
1 answer:
Scilla [17]3 years ago
7 0

{5}^{5}

is the answer.

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Which of the following mappings represent a function?<br> Group of answer choices
ZanzabumX [31]

Answer:

The first one.

Step-by-step explanation:

A single x value in a relation cannot have more than one y value.

4 0
3 years ago
For triangle Abc side a=18 angle C=90 and side b=24 find side c to the nearest whole number
ollegr [7]
...
Using the Pythagorean theorem, a² + b² = c², we can solve for 'c'.
We know the length of sides 'a' and 'b', and this is all we really need to know. The angle value of angle 'c' is irrelevant to finding the length of side 'c' (which I'm assuming is the hypotenuse).
18² + 24² = c².
324 +  576 = c².
900 = c². Now find the square root of 900 to get the value of 'c'.
30 = c. <= And there is your answer.

3 0
3 years ago
2a. Determine the equation of the line connecting the points (0, -1) and (2, 3) *
Sauron [17]
First create the equation y=Mx+ B

B is the y intercept so when y = 0, B = -1.

Now we have y=Mx - 1

The slope is M. We can calculate this by using the formula M = (y2 -y1) / (x2 - x1)

Use the points (0, -1) and (2,3) for these values. So y2 = 3, y1 = -1, x2 = 2, x1 = 0

Plug them into the equation and solve

M = (3 + 1) / (2 - 0)
M = 4/2 = 2

Now we have the equation y = 2x - 1

Next to figure out if the points given are on the line you take the values and plug them into your equation like so: 4 = 2(-2) - 1

2(-2) - 1 does not equal 4 so this point does not fall on this line. Follow this same procedure for the next point given.
8 0
3 years ago
Simplify (square root 2)( square root of 2^3)
steposvetlana [31]

Answer:

\large\boxed{(\sqrt2)(\sqrt{2^3})=4}

Step-by-step explanation:

(\sqrt2)(\sqrt{2^3})\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\sqrt{2\cdot2^3}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=\sqrt{2^{1+3}}=\sqrt{2^4}\\\\(1)=\sqrt{2^{2\cdot2}}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt{(2^2)^2}\qquad\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=2^2=4\\\\(2)=\sqrt{2\cdot2\cdot2\cdot2}=\sqrt{16}=6\ \text{because}\ 4^2=16

8 0
3 years ago
Yolanda used a reconciliation worksheet provided by her bank. Line 5 should equal line 6 at the end of the reconciliation, but i
forsale [732]

Answer is 19.99 dollars

Explanation:

Let us draw the reconciliatin done by Yolanda linewise

Banking reconciliation Worksheet Amount of Mega

1) Closing balance                                                       $ 345 89

2) the sum of any outstanding deposits or credits.         0.00

3)   Sum of 1 and 2                                                          345.89

4. sum of any outstanding checks or debits.                $ 37 51 5.

5) (3)-(4)                                                                           $ 308 38

6) checkbook balance.                                                   $ 328 37  

7) Difference (6)-(5)                                                         $   19.99


SInce difference is exactly 19.99 dollars Yolanda should look for the amount 19.99 dollars to find a solution to the problem i.e. to see the reason for the difference between lines 5 and 6                

4 0
3 years ago
Read 2 more answers
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