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Musya8 [376]
3 years ago
6

Diana is painting statues. She has \dfrac{7}{8} 8 7 ​ start fraction, 7, divided by, 8, end fraction of a liter of paint remaini

ng. Each statue requires \dfrac{1}{20} 20 1 ​ start fraction, 1, divided by, 20, end fraction of a liter of paint. How many statues can she paint?
Mathematics
2 answers:
Lostsunrise [7]3 years ago
8 0

Answer: 35/2

Step-by-step explanation:

anzhelika [568]3 years ago
3 0

Answer:

Number of statues that can be painted are 17

Step-by-step explanation:

Initially Diana has \frac{7}{8} liters of paint remaining.

Every statue requires \frac{1}{20} liters of paint for painting.

We have to find how many statues we will be able to paint with this remaining paint.

To get the number of statues,

Number of statues = \frac{Paint remaining}{Paint required for 1 statue}

number of statues = \frac{\frac{7}{8} }{\frac{1}{20} }

                               = \frac{35}{2} = 17.5

Since the number of statues is not an integer the maximum number of statues that can be painted are 17.

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What’s the least common denominator of 9,2 and 17
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The answer is 54

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3 years ago
What is the surface area of a cube that has a side length of 5 feet?
harkovskaia [24]

Hello!

<h3><em><u>Answer</u></em></h3><h3 />

The surface area of the cube is 150 ft^{2}.


<h3><em><u>Explanation</u></em></h3>

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6 0
2 years ago
A high school principal wishes to estimate how well his students are doing in math. Using 40 randomly chosen tests, he finds tha
ollegr [7]

Answer:

99% confidence interval for the population proportion of passing test scores is [0.5986 , 0.9414].

Step-by-step explanation:

We are given that a high school principal wishes to estimate how well his students are doing in math.

Using 40 randomly chosen tests, he finds that 77% of them received a passing grade.

Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;

                          P.Q. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of students received a passing grade = 77%

           n = sample of tests = 40

           p = population proportion

<em>Here for constructing 99% confidence interval we have used One-sample z proportion test statistics.</em>

So, 99% confidence interval for the population proportion, p is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99  {As the critical value of z at 0.5%

                                           level of significance are -2.5758 & 2.5758}  

P(-2.5758 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 2.5758) = 0.99

P( -2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.99

P( \hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.99

<u>99% confidence interval for p</u> = [\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }]

 = [ 0.77-2.5758 \times {\sqrt{\frac{0.77(1-0.77)}{40} } } , 0.77+2.5758 \times {\sqrt{\frac{0.77(1-0.77)}{40} } } ]

 = [0.5986 , 0.9414]

Therefore, 99% confidence interval for the population proportion of passing test scores is [0.5986 , 0.9414].

Lower bound of interval = 0.5986

Upper bound of interval = 0.9414

6 0
2 years ago
Write 1,700 in exponential form
Artist 52 [7]

The correct answer is 1.7 times 10^3.

8 0
2 years ago
Read 2 more answers
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