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denis-greek [22]
3 years ago
10

Consider the function m(t) = -28/5t

Mathematics
1 answer:
Inga [223]3 years ago
7 0

Answer:

C

Step-by-step explanation:

C

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Math homework please help new subject dont know it. (trolls = report)
Natasha2012 [34]
Find area on triangle:
A=(1/2)bh
A=(1/2)(8 units)(6 units)
A=(1/2)(48 units^2)
A=24 units^2
Just do the same for the rest of this page following the equation for the area of a triangle A=(1/2)(base)(height)

Find the error:
A=(1/2)bh
100m^2=(1/2)b(20m)
100m^2=(10m)b
10m=b
He forgot to multiply bh by 1/2

Area of parallelogram:
A=bh
A=(3 units)(3 units)
A= 9 units^2
The red line is the height and the bottom of the parallelogram is the base, just count the squares. Imagine cutting the parallelogram at the red line and moving that triangle piece to the other side, it’ll make a rectangle, that’s why the equation is the same.
6 0
3 years ago
Read 2 more answers
Write 6000370 in scientific notation
svetlana [45]

Answer:

6.00037 x 10^6

Step-by-step explanation:

6000370 in scientific notation

= 6.00037 x 10^6

6 0
3 years ago
Read 2 more answers
Atrice needs to find a container that will hold at least 300 cubic Inches of water. Which of these figures could atrice use
Tju [1.3M]

Answer:I think it’s answer B

Step-by-step explanation:because if you measure figure 2 it will be about 451 and you need it to hold about 300 so it can’t be a or c and figure 3 holds about 321 while figure 1 holds about something so I think it’s B

4 0
3 years ago
What is the volume of the prism if the base is 8 feet and the volume is 48 feet
Delvig [45]

Answer:

48

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Given that for an arithmetic sequence, the first term is q and the second term is qz.
otez555 [7]

Answer:

d = q(z-1)

S_n = \frac{nq}{2}(2 + (n-1)(z-1))

S_{10} = 5q(9z -7)

Step-by-step explanation:

Given

T_1 = q

T_2 = qz

Solving (a1): The common difference (d)

d is calculated as

d  = T_2 - T_1

This gives:

d  = qz - q

Factorize:

d = q(z-1)

Solving (a2): Sum of n terms

This is calculated using:

S_n = \frac{n}{2}(2*T_1 + (n-1)d)

Substitute values for T1 and d

S_n = \frac{n}{2}(2*q + (n-1)q(z-1))

S_n = \frac{n}{2}(2q + q(n-1)(z-1))

Factorize:

S_n = \frac{n}{2}(q(2 + (n-1)(z-1)))

S_n = \frac{nq}{2}(2 + (n-1)(z-1))

Solving (b): Sum of first 10.

In this case, n = 10

So:

S_n = \frac{nq}{2}(2 + (n-1)(z-1))

becomes

S_{10} = \frac{10 * q}{2}(2 + (10-1)(z-1))

S_{10} = 5 * q(2 + 9(z-1))

S_{10} = 5q(2 + 9(z-1))

S_{10} = 5q(2 + 9z-9)

S_{10} = 5q(2 -9+ 9z)

S_{10} = 5q(-7+ 9z)

S_{10} = 5q(9z -7)

4 0
3 years ago
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