All categories

3 years ago

How do you do this fraction

Mathematics

2 answers:

JulsSmile [24]3 years ago

7 0

The answer to the question is 11/14

wolverine [178]3 years ago

6 0

Write 11
----
14

when adding fractions with common denominators, you never add the denominators. only the numerators, and keep the denominators the same

You might be interested in

H(x)=1/8x^3-x^2 Over which interval does h have a positive average rate of change?

lara31 [8.8K]

Answer:

$(-\infty,0)\cup(\frac{16}{3},\infty)\\That \ is x\frac{16}{3}$

Step-by-step explanation:

$h(x)=\frac{1}{8}x^{3} -x^{2} \\\\Differentiate \ h(x) \ with \ respect \ to \ x\\h'(x)=\frac{3}{8}x^{2} -2x$

For positive rate of change $h'(x)>0$

$\frac{3}{8} x^{2} -2x>0\\x(\frac{3}{8}x-2)>0\\\\ When \ x0 \ (multiplication \ of \ two \ positives \ is \ positive)\\\\h'(x)>0 \ when \ x\frac{16}{3} \\\\$

6 0

4 years ago

a jar contains 2 red and 4 blue marbles. a marble is drawn from the jar. what is the probability that a red marble will be drawn

Lubov Fominskaja [6]

2 red / 4 blu

just semplify

1 red / 2 blu

so the probability is

1/2

7 0

3 years ago

Read 2 more answers

Find the value of each missing variable

Vinvika [58]

Answer:

x=90

y=78

z=70

Now

or,90+78+70

or,238 answer.

4 0

2 years ago

Jason is driving at 55 mph. He needs to keep his car within 5 miles per hour of his current speed. Write and solve an absolute v

djverab [1.8K]

Maximum speed: 55mph + 5mph = 60mph
minimum speed: 55mph - 5mph = 50mph
Hope this helped?

5 0

3 years ago

The original line has the equation of y=-2x+8

enot [183]

The new equation of line that is perpendicular to the original that goes through the point (6, -1) in slope intercept form is $y = \frac{1}{2}x - 4$

<h3>Solution:</h3>

Given that original line has the equation of y = -2x + 8

We have to write a new equation that is perpendicular to the original that goes through the point (6, -1)

Let us first find slope of original line

The slope intercept form of line is given as:

y = mx + c ------ eqn 1

Where "m" is the slope of line and "c" is the y - intercept

On comparing the slope intercept form and given original equation, we get "m = -2"

Thus slope of original line "m" = -2

We know that product of slope of a line and slope of line perpendicular to it are always -1

slope of original line x slope of line perpendicular to it = -1

$\begin{array}{l}{-2 \times \text { slope of line perpendicular to it }=-1} \\\\ {\text { slope of line perpendicular to it }=\frac{1}{2}}\end{array}$

Let us find equation of line with slope m = 1/2 and passes through point (6, - 1)

Substitute $m = \frac{1}{2}$ and (x, y) = (6, -1) in eqn 1

$-1 = \frac{1}{2} \times 6 + c\\\\-1 = 3 + c\\\\c = -4$

Thus the required equation of line is:

Substitute "c" = -4 and $m = \frac{1}{2}$ in eqn 1

$y = \frac{1}{2}x - 4$

Thus the equation of line perpendicular to original line is found

7 0

3 years ago