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vodomira [7]
3 years ago
6

FOR 50 POINTSSS PLSSS HELPPP IF U HELP ILL SEND 30 MORE POINTSSS

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
8 0

Answer:

1. t=21+4

2. 25º

Step-by-step explanation:

1. let t=temperature. its 21 now, which is 4 less than it was before, so you add

2. 21+4=25º

hope this helps have a great day/night!!! :))

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carries family leaves at 7:15. they drive for 30 minutes and yhen stop for dinner what time is it when they stop for dinner?
laiz [17]

Answer:

I think it is 7:45

Step-by-step explanation:


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4 years ago
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A clothing store is offering 40% off of any sale merchandise. Chester's subtotal is $128.00. What is his total after the discoun
S_A_V [24]

Answer:

should be 76.8

Step-by-step explanation:

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3 years ago
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Simplify <br> 3(x - 6) - 4(x + 3).<br> A)-x - 30<br> B)-x - 9<br> C)-x - 6 <br> D)-x - 30
morpeh [17]

Answer:

-x-30

Step-by-step explanation:

<em>first you need to </em><em>distribute</em><em>:</em>

<em>3(x)+3(-6) -4(x)+ (-4)(3)</em>

<em>Then you </em><em>multiply:</em>

<em>3x+(-18)-4x+(-7)</em>

<em>then you </em><em>combine like terms:</em>

<em>3x-4x= -1x </em>

<em>-18+(-7)= -25</em>

<em>simplified:</em>

<u><em>-1x-30</em></u>

3 0
4 years ago
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The length of the side sqaure A is 50% OF THE LENGTH OF THE SIDE SQUARE b
UNO [17]

Let's say the side length of square A is x, which means the side length of square B is 2x.

Then, the area of square A can be written as , and the area of square B can be written as .

There's no diagram here with shaded region, so I'll just find the area of square A as a percentage of the area of square B:

= 1/4 = 25%

So, the answer is 25% (note this is the answer to the question: "express the area of square A as a percentage of the area of square B; there is no diagram showing me where the shaded area is, so I cannot answer the original question

4 0
2 years ago
Find parametric equations and symmetric equations for the line. (Use the parameter t.) The line through (4, −5, 2) and parallel
Nataliya [291]

Answer:

Step-by-step explanation:

From the given information, the symmetric equations for the line pass through(4, -5, 2) i.e (x_o, y_o, z_o) and are parallel to \dfrac{x+5}{1} = \dfrac{y}{2}= \dfrac{z-3}{1}

The parallel vector to the line i + zj+k = ai + bj + ck

Hence, the equation for the line is :

x = x_o + at \\ \\ x = y_o + bt \\ \\ x = z_o + ct

x = 4 + t

y = -5 + 2t

z = 2 + t

Thus, x, y, z = ( 4+t, -5+2t, 2+t )

The symmetric equation can now be as follows:

\begin  {vmatrix} x = 4+ t   \\ \\  \dfrac{x-4}{1} = t  \begin {vmatirx} \end {vmatrix}\begin {vmatrix} y = - 5+2t  \\ \\ \dfrac{y+5}{2}  =t      \end {vmatrix}\begin {vmatrix} z =2+t  \\ \\ \dfrac{z-2}{1}  =t      \end {vmatrix}

∴

\dfrac{x-4}{1}= \dfrac{y+5}{2}=\dfrac{z-2}{1}

8 0
3 years ago
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