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Ostrovityanka [42]
3 years ago
8

Can someone explain these two math questions to me? −2 + 4 ⋅ 32 − 6 5 + 42 ÷ 2(3)

Mathematics
2 answers:
zepelin [54]3 years ago
8 0
The first one would be 120 the second one would be 68
Solnce55 [7]3 years ago
5 0
So, if you are trying to solve this, you would have to use PEMDAS. so how you would solve this is,you would multiply first then add and subtract. 
-2+4* 32-6= (steps below)
4* 32=128
-2+128- 6= 120. 
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What is 16,107,320 written in word form
Colt1911 [192]
Sixteen million one hundred seven thousand three hundred and twenty
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3 years ago
Point GG is located at (-4,2)(−4,2) on the coordinate plane. Point GG is reflected over the xx-axis to create point G'G ′ . What
Taya2010 [7]

Answer: (4,2)

Step-by-step explanation:

When a point is reflected over the x axis, only the x value changes to the opposite sign (positive or negative). The y value doesn’t change.

7 0
3 years ago
A 1 newton force will stretch a spring 1 meter. The spring/mass system is damped by a force that is 8 times the instantaneous ve
sukhopar [10]

Answer:

Step-by-step explanation:

Given the mass is m =16kg, and 1N force will stretch the spring 1 m.

That is, F =1N,Z =1m. Now find the spring constant k:

F = kL = 1 = k(1) = k= 1N/m.

The damping force is 8times the instantaneous velocity, this means β = 8,

and the external force is f(t) = 0

Initially the object compressed 0.6m above equilibrium position,

with the downward velocity is 2m/s.

The differential equation for a spring mass system with

damping force and extemal force is: mx" + βxt + kx = f(t).

so, 16x"+ 8x' + x= 0, x(0} = -0.6, x'(0)= 2m/s.

Now solve the DE:

The auxilary equation for the homogeneous equation is 16x"+8x'+x=0

solving we get, 16r² + 8r + 1 = 0 => (4r + 1)² = 0 => r = - 1/4.

Then the general solution for the homogenous system is: x(t)=c_1e^{-t/4} +c_2te^{-t\4}.

Use the initial conditions x (0) = -0.6, x'(0) = 2m/s:

x(0)=c_1e^{0} +c_2(0)e^{0}=-0.6=c_1\\x'(t)=-\frac{1}{4}c_1e^{-t/4}+c_2e^{-t/4}-\frac{1}{4}c_2te^{-t/4}\\x'(0)=-\frac{1}{4}c_1e^0+c_2e^0-\frac{1}{4}c_2(0)e^0=2=-\frac{1}{4}(-0.6)+c_2=c_2=1.85.

Hence, x(t) =-0.6e^{-t/4}+1.85te^{-t/4}.

5 0
3 years ago
A price decreased from 60$ to 45$ find the percent of decrease
BlackZzzverrR [31]
Percent change = [(45 - 60) / 60] x 100 = -25 % (decrease)
8 0
3 years ago
Read 2 more answers
Solve for x.<br><br> 2/3(x−7)=−2
zaharov [31]
2/3x - 14/3 = -2
3(2/3x - 14/3) = -2(3)
           2x - 14 = -6
                   2x = -6 + 14
                   2x = 8
                     x = 8/2
                     x= 4

hope this helps :)



5 0
3 years ago
Read 2 more answers
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