All categories

3 years ago

Which shapes have parallel sides

Mathematics

1 answer:

guajiro [1.7K]3 years ago

3 0

Answer:

All parallelograms have at least 1 parallel side.(Rectangles,squares,rhombuses,etc.)Trapezoids also have parallel sides.

Step-by-step explanation:

You might be interested in

Thirty percent of all customers who enter a department store will make a purchase. Suppose that 6 customers enter the store and

torisob [31]

Answer:

Step-by-step explanation:

Let's use binomial distribution, because we are interested in find the total number of successes in a sequence of n independent experiments.

In probability, a binomial distribution is used in a Bernoulli process. That is, a sequence of experiments of n independent trials, each asking a dichotomous question, that means it only has two answers. One answer is a success (probability: p) and the other is a failure (probability: 1-p). In this case, every customer who enters in the store is the experiment. If they make a purchase is a success event, taking into account that every purchase decision has to be independent.

$P(X=x) = C(n,x)p^{x} (1-p)^{n-x}$

x= total number of success

n= total number of experiments

p=probability of success on an indivual trial

$C(n,x) = \frac{n!}{x!(n-x)!}$

a) x= 5 ------> customers that make a purchase

n= 6 ------> total customers

p=0.3

$p(X=5)= C(6,5)(0.3)^{5} (1-0.3)^{6-5} \\p(X=5)=0.102$

b) At least 3 customers make a purchase. x ≥ 3

$P(X\geq 3)=1-P (X=0)-P(X=1)-P(X=2)\\P(X\geq 3)=1-(C(6,0)(0.3^{0})(0.7)^{6}) - (C(6,1)(0.3^{1})(0.7)^{5}) - (C(6,2)(0.3^{2})(0.7)^{4})\\ P(X\geq 3) = 1-0.11765-0.30253-0.32414\\P(X\geq3)= 0.2557$

c) At most 2 customers make a purchase. x ≤ 2

$P(X\leq2) = P(X=0) + P(X=1) + P(X=2)\\P(X\leq2) = (C(6,0)(0.3^{0})(0.7)^{6}) + (C(6,1)(0.3^{1})(0.7)^{5}) + (C(6,2)(0.3^{2})(0.7)^{4})\\P(X\leq2) = 0.11765-0.30253-0.32414\\P(X\leq2)=0.7443$

d)At least 1 customer makes a purchase. x ≥ 1

$P(X\geq 1)=1-P(X=0)\\P(X\geq 1)= 1-C(0,6)(0.3)^{0}(0.7)^{6} \\P(X\geq 1)= 1-0.11765 = 0.8824$

e)They must be kind to customers, always willing to help and give information about products clearly and honestly.

Have enough inventory and offer promotions for the purchase of more than one product

Have an agile payment system that avoids rows and delays in purchases.

6 0

3 years ago

D. Congruent <br> If you get this right I will mark you as a brainliest

IRISSAK [1]

Concentric as they have same center

6 0

3 years ago

A vector has an x-component of −24.5 units and a y-component of 31.5 units. Find the magnitude and direction of the vector.

jasenka [17]

we are given a vector

whose

x-component is -24.5

so, $v_x=-24.5$

y-component is 31.5

so, $v_y=31.5$

Magnitude:

we can use formula

$|v|=\sqrt{(v_x)^2+(v_y)^2}$

we can plug values

$|v|=\sqrt{(-24.5)^2+(31.5)^2}$

$|v|=39.90614$

Direction:

we can use direction formula

$\theta=tan^{-1}(\frac{v_y}{v_x})$

now, we can plug values

$\theta=tan^{-1}(\frac{31.5}{-24.5})$

$\theta=180-52.12$

$\theta=127.88$ ................Answer

8 0

3 years ago

A population has a mean of 200 and a standard deviation of 50. Suppose a sample of size 100 is selected and x is used to estimat

AveGali [126]

Answer:

a) 68% probability that the sample mean will be within ±5 of the population mean.

b) 95% probability that the sample mean will be within ±10 of the population mean.

Step-by-step explanation:

To solve this problem, we have to understand the Empirical Rule and the Central Limit Theorem

Empirical Rule

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $s= \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

Mean: $\mu = 200$

Standard deviation of the population: $\sigma = 50$

Size of the sample: $n = 100$

Standard deviation for the sample mean: $s = \frac{50}{\sqrt{100}} = 5$

a.What is the probability that the sample mean will be within ±5 of the population mean?

5 is one standard deviation from the mean.

By the Empirical Rule, 68% probability that the sample mean will be within ±5 of the population mean.

b.What is the probability that the sample mean will be within ±10 of the population mean?

10 is two standard deviations from the mean

By the Empirical Rule, 95% probability that the sample mean will be within ±10 of the population mean.

4 0

3 years ago

The spinner to the right contains three letters of the alphabet. What is the probability of getting exactly one A in three spins

yulyashka [42]

Answer:

the probability is 1/3 in decimal it is i think 33.33 and i percentage it is 33%

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers