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oksian1 [2.3K]
3 years ago
9

In physics how much energy is required to raise the temp of 9.78kg of water from 40.82c to 52.07c? The specific heat of water in

this state is 4186j/kg-c.
Physics
2 answers:
Sati [7]3 years ago
7 0

Answer:

469.6KJ

Explanation:

Heat energy required can be calculated using the formula

H = mc∆t where

m is the mass of the water

c is the specific heat capacity of the water

∆t is the change in temperature of the water

Given m = 9.78kg

c = 4186j/kg-c.

∆t = 52.07°C - 40.82°C

∆t = 11.25°C

H = 9.78 × 4186 × 11.25

H = 460,564.65Joules

= 460.6KJ

Nat2105 [25]3 years ago
7 0

Answer:

the amount of energy required to raise the temperature of the water is 460564.65 J

Explanation:

The energy required to raise the temperature of water can be calculated as follows;

Q = mcΔθ

where;

Q is the quantity of heat or energy required to raise the temperature of water

m is mass of water

c is specific heat capacity of water

Δθ is change in temperature = T₂ - T₁

Given;

m =  9.78kg

c = 4186j/kg-c

Δθ = T₂ - T₁ = 52.07°C - 40.82°C  = 11.25°C

Q = mcΔθ

Q = (9.78)(4186)(11.25)

Q = 460564.65 J

Therefore, the amount of energy required to raise the temperature of the water is 460564.65 J

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A 15-kg block at rest on a horizontal frictionless surface is attached to a very light ideal spring of force constant 450 N/m. T
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