Explanation:
Each resistor has a resistance of R.
In the first problem, each row of three resistors in series has a resistance or 3R.
A₂ = 4A, so the voltage drop across the rows is:
V = IR
V = (4)(3R)
V = 12R
The voltage drop equals the voltage gain (Kirchoff's voltage law). The battery has a voltage of 9V, so:
9 = 12R
R = 0.75 Ω
The three rows are in parallel with each other, so the total resistance is:
∑R = (1/(3R) + 1/(3R) + 1/(3R))⁻¹
∑R = R
∑R = 0.75 Ω
The current A₁ can be found with Ohm's law:
V = IR
9 = (A₁) (0.75)
A₁ = 12 A
Using Ohm's law to find V₁, V₂, and V₃:
V = IR
V₁ = (4)(0.75)
V₁ = 3V
V₂ = (4)(2×0.75)
V₂ = 6 V
V₃ = (4)(3×0.75)
V₃ = 9 V
In the second problem, all the resistors are in series. So the total resistance is:
∑R = 8R
The battery voltage is 16V, and A₂ = 6A. So using Ohm's law:
V = IR
16 = (6)(8R)
R = 1/3 Ω
Since there's only one loop, the current is the same at all points. So A₁ = A₂ = 6A.
Using Ohm's law to find each voltage:
V = IR
V₁ = (6)(1/3)
V₁ = 2V
V₂ = (6)(2×1/3)
V₂ = 4 V
V₃ = (6)(4×1/3)
V₃ = 8 V
V₄ = (6)(2×1/3)
V₄ = 4 V
Answer: Quantum is really just an amount of any physical entity involved in an interaction.
Explanation:
Hey will use a container called a graduated cylinder to measure liquids<span>. Graduated cylinders have numbers on the side that help you determine the volume</span><span>. Volume</span><span> is measured </span><span>in units called liters or fractions of liters called milliliters (ml).</span>