Given Information:
Radius = ra = 2.60 cm = 0.026 m
Density = J = 15.0 nC/m
change in potential difference = ΔV = 200 V
Required Information:
Distance = d = ?
Answer:
distance = 0.088 m
Explanation:
As we know
ΔV = Vb - Va = J/4πε₀*ln(rb/ra)
Where ra and rb is the point where potential difference is Va and Vb respectively
1/4πε₀ = 9x10⁹ N.m²/C²
We want to find the distance d = rb - ra
ΔV = J/4πε₀*ln(rb/ra)
200 = 9x10⁹*15x10⁻⁹*ln(rb/ra)
200/135 = ln(rb/ra)
1.48 = ln(rb/ra)
taking e on both sides yields
e^(1.48) = rb/ra
4.39 = rb/ra
rb = 4.39*0.026
rb = 0.114 m
Therefore, the required distance is
d = rb - ra
d = 0.114 - 0.026
d = 0.088 m
Therefore, the other probe must be placed 0.088 m from the surface so that the voltmeter reads 200 V
The answer to the correct number of significant figures is 6.774.
<h3>What is quotient?</h3>
When a number(big) divided smaller number, the answer obtained greater than zero is called a quotient.
Divide 143.6 ÷ 21.2
143.6/21.2 = 1436/212
=6.77358
The quotient is rounded to three significant figures after decimal
143.6 ÷ 21.2 = 6.774
Thus, the answer to the correct number of significant figures is 6.774
Learn more about quotient
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3/5•(4e+5kg)
:
Factor out 3/5 from the expression
3/5•(4e+5k)
Use the commutative property to reorder the terms
3/5(4e+5k)
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