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zzz [600]
3 years ago
7

Rebecca has r number of crayons. Julie has 17 more crayons than Rebecca. Which expressions correctly show the number of crayons

that Julie has?
17 - r
r - 17
r + 17
17 + r
none of the above
Mathematics
2 answers:
Sedaia [141]3 years ago
7 0

Answer:

I would say that it is none of the above that one is much more reasonable than the other ones

Step-by-step explanation:


zalisa [80]3 years ago
4 0

Answer:r+17,17+r

Step-by-step explanation:

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A restaurant offers the following limited lunch menu:. Main Courses: Beef, Pork Roast, Duck, Quiche. Vegetables: Broccoli, Carro
max2010maxim [7]
The correct answer to this question is "120 ways"

Main Courses consists of Beef, Pork Roast, Duck, Quiche (4), Vegetables consists of Broccoli, Carrots, Potatoes (3), Beverages consists of Coffee, Tea, Milk, Soda and Shakes (5), Desserts consists of Ice Cream, Brownies (2)

The total number of ways can be solved as: 4 * 3 * 5 * 2 = 120
5 0
3 years ago
May someone help me out with this please
lions [1.4K]
To work out 7% of 600, this is what you do
7/100 x 600 
this will give you your answer 
7% of 600 = 42
7 0
3 years ago
When you subtract 8from 10 what is the different​
Alinara [238K]

Answer:

2

Step-by-step explanation:

Difference = 10 - 8 = 2

Hope it helps you in your learning process.

8 0
3 years ago
Drag the expressions into the boxes to correctly complete the table.
lora16 [44]

Answer:

SUMMARY:

x^4+\frac{5}{x^3}-\sqrt{x}+8                               →    Not a Polynomial

-x^5+7x-\frac{1}{2}x^2+9                           →    A Polynomial

x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi              →    A Polynomial

\left|x\right|^2+4\sqrt{x}-2                                   →    Not a Polynomial

x^3-4x-3                                        →    A Polynomial

\frac{4}{x^2-4x+3}                                              →    Not a Polynomial

Step-by-step explanation:

The algebraic expressions are said to be the polynomials in one variable which consist of terms in the form ax^n.

Here:

n = non-negative integer

a = is a real number (also the the coefficient of the term).

Lets check whether the Algebraic Expression are polynomials or not.

Given the expression

x^4+\frac{5}{x^3}-\sqrt{x}+8

If an algebraic expression contains a radical in it then it isn’t a polynomial. In the given algebraic expression contains \sqrt{x}, so it is not a polynomial.

Also it contains the term \frac{5}{x^3} which can be written as 5x^{-3}, meaning this algebraic expression really has a negative exponent in it which is not allowed. Therefore, the expression x^4+\frac{5}{x^3}-\sqrt{x}+8 is not a polynomial.

Given the expression

-x^5+7x-\frac{1}{2}x^2+9

This algebraic expression is a polynomial. The degree of a polynomial in one variable is considered to be the largest power in the polynomial. Therefore, the algebraic expression is a polynomial is a polynomial with degree 5.

Given the expression

x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi

in a polynomial with a degree 4. Notice, the coefficient of the term can be in radical. No issue!

Given the expression

\left|x\right|^2+4\sqrt{x}-2

is not a polynomial because algebraic expression contains a radical in it.

Given the expression

x^3-4x-3

a polynomial with a degree 3. As it does not violate any condition as mentioned above.

Given the expression

\frac{4}{x^2-4x+3}

\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}

Therefore, is not a polynomial because algebraic expression really has a negative exponent in it which is not allowed.

SUMMARY:

x^4+\frac{5}{x^3}-\sqrt{x}+8                               →    Not a Polynomial

-x^5+7x-\frac{1}{2}x^2+9                           →    A Polynomial

x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi              →    A Polynomial

\left|x\right|^2+4\sqrt{x}-2                                   →    Not a Polynomial

x^3-4x-3                                        →    A Polynomial

\frac{4}{x^2-4x+3}                                              →    Not a Polynomial

3 0
3 years ago
Through: (1,5), perp. to y=-1/10x + 3<br> pls help
Sedbober [7]
First to get the equation you knew to understand one thing about perpendicular lines. The slope of the line is the opposite reciprocal of the perpendicular lines or the new slope is m = 10.

Then you use the formula
y = mx + b
you plug in your values from the point and the new slope.
(1,5) with new slope m
5= 10(1)+b
5-10=b
-5 = b
then make your new equation
y = 10x -5
that's your line that goes through point (1,5) and is perpendicular to the line given
8 0
3 years ago
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