All categories

3 years ago

What is 4/3 subtracted by 2/5

Mathematics

2 answers:

yKpoI14uk [10]3 years ago

7 0

In order to subtract fractions, we must find a common denominator, then subtract the numerators.

The common denominator (LCM(3, 5)) is 15.

We must multiply the first numerator by 5, because 3*5=15 and the second numerator by 3 because 5*3=15.

We get $\frac{20}{15} - \frac{6}{15}$ .

All we need to do now is subtract the numerators: $\frac{14}{15}$ .

The answer is 14/15.

ExtremeBDS [4]3 years ago

7 0

=4/3 - 2/5

=5 x 4/ 3 x 5 - 2 x 3/ 5 x 3

=20/15 - 6/15

=14/15

You might be interested in

Urgent! <br><br> 1 1/6 - 3/6 =?

Mnenie [13.5K]

Answer:

1 4/6

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

I need to determine each angles measure. M 4<br><br> M 6

Ulleksa [173]

By geometrical inspection we have:
M4 = 30
Then the angle M6 can be determined from the fact that you have a rectangle triangle (345) that has an angle of 90 and another of 30. The missing angle measures:
180-90-30 = 60 = M3
Then to find M6 we have
M3 + 60 + M6 = 180
M6 = 180-60-M3
M6 = 180-60-60
M6 = 60
answer:
M4 = 30
M6 = 60

7 0

3 years ago

What is the decimal equivalent of the -68/255

Juli2301 [7.4K]

The answer is -0.266666667.
Round how you need

8 0

3 years ago

WILL GIVE BRAINLIEST! NEED FAST!

dybincka [34]

Answer:

650=65% of 1000

Step-by-step explanation:

650-600=65 or 65%

3 0

3 years ago

A 90 percent confidence interval is to be created to estimate the proportion of television viewers in a certain area who favor m

Dominik [7]

Answer:

This means that the first interval, with 9000 viewers, is 3 times as narrower as the second interval, with 1000 viewers.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The width of the interval is:

$W = 2z\sqrt{\frac{\pi(1-\pi)}{n}}$

In this sample:

Two 90% intervals, with different lenghts. So both have the same values for z an $\pi$

Interval A:

9000 viewers.

So the width is

$W_{A} = 2z\sqrt{\frac{\pi(1-\pi)}{9000}}$

Interval B:

100 viewers

So the width is

$W_{B} = 2z\sqrt{\frac{\pi(1-\pi)}{1000}}$

Relationship between the widths:

$R = \frac{W_{A}}{W_{B}} = \frac{2z\sqrt{\frac{\pi(1-\pi)}{9000}}}{2z\sqrt{\frac{\pi(1-\pi)}{1000}}} = \frac{\sqrt{1000}}{\sqrt{9000}} = \frac{\sqrt{1}}{\sqrt{9}} = \frac{1}{3}$

This means that the first interval, with 9000 viewers, is 3 times as narrower as the second interval, with 1000 viewers.

8 0

3 years ago