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3 years ago

Rosa is three times as old as her daughter the sum of their ages is 44 years . how old is maria

Mathematics

1 answer:

serious [3.7K]3 years ago

4 0

Is maria her daughter? if assuming so, maria is 44 divided by 4 which is equals to 11 years old.

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If the measure of 0 is A radians and B degrees, then A=180B/pie

yKpoI14uk [10]

Yup that is correct, that is the way to convert measurements of angle from radians to degrees. because 2pi is equivalent to one revolution of a circle and in degrees is equal to 360 degrees, then simplifying it 360 / 2pi = 180 / pi.
so the measure of 0 is A radians and B degrees, then A = 180 B/pi

3 0

3 years ago

Hiiii help please ahh

Brilliant_brown [7]

Answer:

Question 1 Answer : x^2 - 2y^2

Question 2 Answer: x^2 $\pi$ - 36 $\pi$

7 0

2 years ago

Read 2 more answers

Multi-step) -3(y + 7) + 8 = -28 Unit Mrs. Each How Answer

SSSSS [86.1K]

-3y -21 +8 = -28
-3y -13 = -28
-3y = -15
y= 5

4 0

3 years ago

I don’t get this one but the question was something about finding the equation.

Alina [70]

9514 1404 393

Answer:

y = -(x -3)^2 +2

Step-by-step explanation:

The vertex form of the equation for a parabola is ...

y = a(x -h)^2 +k

where the vertex is (h, k) and the value 'a' is a vertical scale factor.

The value of 'a' can be found by looking at the y-value of points ±1 either side of the vertex relative to the vertex. Here, the vertex y-value is +2 at x=3, and either side goes down 1 unit (to y=1) for 1 unit to the right or left. So, a = -1.

Using the values we've read from the graph for the vertex (h, k) = (3, 2) and the scale factor a = -1, we can write the equation as ...

y = -(x -3)^2 +2

4 0

3 years ago

*Asymptotes* g(x) =2x+1/x-3 Give the domain and x and y intercepts

Nataly [62]

Answer: Assuming the function is $g(x)=\frac{2x+1}{x-3}$ :

The x-intercept is $(\frac{-1}{2},0)$ .

The y-intercept is $(0,\frac{-1}{3})$ .

The horizontal asymptote is $y=2$ .

The vertical asymptote is $x=3$ .

Step-by-step explanation:

I'm going to assume the function is: $g(x)=\frac{2x+1}{x-3}$ and not $g(x)=2x+\frac{1}{x}-3$ .

So we are looking at $g(x)=\frac{2x+1}{x-3}$ .

The x-intercept is when y is 0 (when g(x) is 0).

Replace g(x) with 0.

$0=\frac{2x+1}{x-3}$

A fraction is only 0 when it's numerator is 0. You are really just solving:

$0=2x+1$

Subtract 1 on both sides:

$-1=2x$

Divide both sides by 2:

$\frac{-1}{2}=x$

The x-intercept is $(\frac{-1}{2},0)$ .

The y-intercept is when x is 0.

Replace x with 0.

$g(0)=\frac{2(0)+1}{0-3}$

$y=\frac{2(0)+1}{0-3}$

$y=\frac{0+1}{-3}$

$y=\frac{1}{-3}$

$y=-\frac{1}{3}$ .

The y-intercept is $(0,\frac{-1}{3})$ .

The vertical asymptote is when the denominator is 0 without making the top 0 also.

So the deliminator is 0 when x-3=0.

Solve x-3=0.

Add 3 on both sides:

x=3

Plugging 3 into the top gives 2(3)+1=6+1=7.

So we have a vertical asymptote at x=3.

Now let's look at the horizontal asymptote.

I could tell you if the degrees match that the horizontal asymptote is just the leading coefficient of the top over the leading coefficient of the bottom which means are horizontal asymptote is $y=\frac{2}{1}$ . After simplifying you could just say the horizontal asymptote is $y=2$ .

Or!

I could do some division to make it more clear. The way I'm going to do this certain division is rewriting the top in terms of (x-3).

$y=\frac{2x+1}{x-3}=\frac{2(x-3)+7}{x-3}=\frac{2(x-3)}{x-3}+\frac{7}{x-3}$

$y=2+\frac{7}{x-3}$

So you can think it like this what value will y never be here.

7/(x-3) will never be 0 because 7 will never be 0.

So y will never be 2+0=2.

The horizontal asymptote is y=2.

(Disclaimer: There are some functions that will cross over their horizontal asymptote early on.)

6 0

3 years ago