The elastic potential energy in the spring is 1 J
Explanation:
The elastic potential energy stored in a spring is given by:

where
k is the spring constant
x is the stretching/compression of the spring with respect to the unstretched length
For the spring in this problem, we have:
k = 200 N/m is its spring constant
The spring is stretched by 5.0 cm first and then by an additional 5.0 cm, so the total stretching is

Therefore, the elastic potential energy in the spring is:

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