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Ray Of Light [21]

3 years ago

9

Predict how heat would flow if beaker A is moved so that it's touching beaker B A. Heat would flow from beaker B to beaker A. B.

No heat flow would take place between the beakers. C. Heat would flow from both beakers. D. Heat would flow from beaker A to beaker B.

1 answer:

jek_recluse [69]3 years ago

6 0

Zeroth Law of Thermodynamics, which in turn will mean the heat will transfer between both of them up to the point where they are in thermodynamic equilibrium. So the answer is C.

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A stereo speaker is rated at P1000 = 52 W of output at 1000 Hz. At 20 Hz, the sound intensity level LaTeX: \betaβ decreases by 1

baherus [9]

Answer:

The value of the power is $P_c = 38.55 \ W$

Explanation:

From the question we are told that

The power rating $P_{1000} =P_b= 52 \ W$

The frequency is $f = 1000 \ Hz$

The frequency at which the sound intensity decreases $f_k = 20 \ Hz$

The decrease in intensity is by $\beta = 1.3 dB$

Generally the initial intensity of the speaker is mathematically represented as

$\beta_1 = 10 log_{10} [\frac{P_b}{P_a} ]$

Generally the intensity of the speaker after it has been decreased is

$\beta_2 = 10 log_{10} [\frac{P_c}{P_a} ]$

So

$\beta_1-\beta_2 = 10 log_{10} [\frac{P_c}{P_a} ]- 10 log_{10} [\frac{P_b}{P_a} ]$

=> $\beta = 10 log_{10} [\frac{P_c}{P_a} ]- 10 log_{10} [\frac{P_b}{P_a} ]= 1.3$

=> $\beta =10log_{10} [\frac{\frac{P_b}{P_a}}{\frac{P_c}{P_a}} ] = 1.3$

=> $\beta =10log_{10} [\frac{P_b}{P_c} ] = 1.3$

=> $10log_{10} [\frac{P_b}{P_c} ] = 1.3$

=> $log_{10} [\frac{P_b}{P_c} ] = 0.13$

taking atilog of both sides

$[\frac{P_b}{P_c} ] = 10^{0.13}$

=> $[\frac{52}{P_c} ] = 10^{0.13}$

=> $P_c = \frac{52}{1.34896}$

=> $P_c = 38.55 \ W$

3 0

3 years ago

I need help, what are the steps to solve this , I don’t understand

Xelga [282]

It is slightly above 48 degrees celsius, so try 48.2 degrees celsius. If that doesn’t work try 48.1 degrees celsius.

4 0

2 years ago

Light propagating in air strikes the surface of a lake. The reflected ray makes 62° angle with the normal. What angle does the r

blondinia [14]

Answer:

(a) 42°

Explanation:

According to the law of reflection:

Angle of incidence = Angle of reflection

So, angle of reflection = 62°

Angle of incidence = 62°

For refraction,

Using Snell's law as:

$n_i\times {sin\theta_i}={n_r}\times{sin\theta_r}$

Where,

${\theta_i}$ is the angle of incidence ( 62.0° )

${\theta_r}$ is the angle of refraction ( ? )

${n_r}$ is the refractive index of the refraction medium (water, n=1.33)

${n_i}$ is the refractive index of the incidence medium (air, n=1)

Hence,

$1\times {sin62.0^0}={1.33}\times{sin\theta_r}$

Angle of refraction = $sin^{-1}0.6639$ = 42°

4 0

3 years ago

I don’t know this one I need help

nikdorinn [45]

D
Using the kinetic energy 1/2mv^2 formula
5*10^5 is the answer

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2 years ago

Acceleration is the change in distance over time. true or false

olganol [36]

the answer is true acceleration is the change in distance over time.
hope this helps

7 0

3 years ago