What does doubling the voltage do to the strength of the electromagnet?

A car slows down at -5.00 m/s^2 until it comes to a stop after traveling 15.0 m. What was the initial speed of the car?

maria [59]

8.66mls = v1

vf2 = vi2 + a(d)
(0mls) squared = visquared + - 5mls squared (15m)
0mls squared = vi2 - 75m squared / s squared
$\sqrt{x}$ 75 m squared/s squared = vi

Hope this helps!

3 0

3 years ago

A physicist is calibrating a spectrometer that uses a diffraction grating to separate light in order of increasing wavelength (λ

cluponka [151]

Answer:

Explanation:

Given

$N=3680 cm^{-1}$

therefore slit spacing $d=\frac{1}{N}=\frac{1}{3680}=2.717\times 10^{-4}\ cm$

since $d\sin \theta =n\lambda$

for $n=1$

$d\sin \theta =\lambda$

Now,at $\theta _1=12.9^{\circ},\Rightarrow \lambda _1=6.0657\times 10^{-7}\ m=606.57\ nm$

at $\theta _2=14.2^{\circ}\Rightarrow \lambda_2=666.5\ nm$

at $\theta _3=15^{\circ}\Rightarrow \lambda_3=703.21\ nm$

5 0

2 years ago

220V and 5A is supplied to the primary coil. The turns ratio is 500. What is the power on the secondary coil?

alisha [4.7K]

Answer: 1100 W

Explanation:

Input power = 220(5) = 1100 W

The transformer will step up/down voltage, but will also step down/up current.

Neglecting hysteresis and other minor losses, the power will remain the same.

4 0

2 years ago

A block of wood is floating in water; it is depressed slightly and then released to oscillate up and down. Assume that the top a

Marysya12 [62]

Explanation:

Equilibrium position in y direction:

W = Fb (Weight of the block is equal to buoyant force)

m*g = V*p*g

V under water = A*h

hence,

m = A*h*p

Using Newton 2nd Law

$-m*\frac{d^2y}{dt^2} = Fb - W\\\\-m*\frac{d^2y}{dt^2} = p*g*(h+y)*A - A*h*p*g\\\\-A*h*p*\frac{d^2y}{dt^2} = y *p*A*g\\\\\frac{d^2y}{dt^2} + \frac{g}{h} * y =0$

Hence, T time period

T = 2*pi*sqrt ( h / g )

4 0

3 years ago

A Car with drives into a solid object with 70 km/h, from which height would it fall if it was in free fall?

Ilya [14]

Answer:

18.9 m.

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 0 m/s

Final velocity (v) = 70 km/h

Height (h) =?

Next, we shall convert 70 km/h to m/s. This can be obtained as follow:

3.6 km/h = 1 m/s

Therefore,

70 km/h = 70 km/h × 1 m/s / 3.6 km/h

70 km/h = 19.44 m/s

Finally, we shall determine the height. This can be obtained as follow:

Initial velocity (u) = 0 m/s

Final velocity (v) = 19.44 m/s

Acceleration due to gravity (g) = 10 m/s²

Height (h) =?

v² = u² + 2gh

19.44² = 0² + (2 × 10 × h)

377.9136 = 0 + 20h

377.9136 = 20h

Divide both side by 20

h = 377.9136 / 20

h = 18.9 m

Thus, the car will fall from a height of 18.9 m

8 0

3 years ago