TV announcer intend to mean "chnage of speed or velocity" by "High rate of speed" and in Physics domain it would mean "acceleration"
Explanation:
It is common to observe TV announcer saying certain events were occurring “with a high rate of speed”. By saying this they intend to mean that the event was rapid in its occurrence. It can also mean that the change in speed of the happening was very rapid/fast.
However, the same terms connote altogether a different expression in Physics domains. Speed is a scalar quantity with no direction. Hence most of the times speed mean velocity when the direction is also provided. “high rate of speed” would mean a change of velocity per unit time which is acceleration. Hence in Physics domain, the term would stand for acceleration.
Complete Question
A skier leaves a ski jump with a horizontal velocity of 29.4 m/s. The instant before she lands three seconds later, the magnitudes of the horizontal and vertical components of her velocity are: Group of answer choices
A 29.4 m/s; 29.4 m/s.
B 41.6 m/s; 41.6 m/s.
C 29.4 m/s; 41.6 m/s.
D 0; 29.4 m/s.
E 29.4 m/s; 0.
Answer:
Correct option is A
Explanation:
From the question we are told that
The horizontal velocity is
The time taken for the jump is
The velocity along the vertical axis is
substituting values
During the jump the horizontal velocity remains the same as there was a direction change
So the correct option is A
Answer:B
Explanation:
Because the Earth's core isn't moving around earth therefore the center of Earth will forever be warm
If force is applied at 30 degree with the horizontal
then first we will find the components of force in two directions
now we can find normal force by balancing the forces in Y direction
now since block is moving with constant speed
so here forces along horizontal plane will be balanced also
Now the weight of the box is defined as
now plug in all values
Answer:
a) Vb = 4.65m/s at 25.46° due south of east
b) t = 119s
c) d = 238m
d) 28.43° due north of east.
e) Vb = 3.69m/s due east
f) t = 135.5s
Explanation:
Velocity relative to the earth is:
Vb = 4.65m/s < -25.46°
Since the distance to travel is 500m:
The distance on the y-axis is given by:
If the final position is directly east from the starting position:
From the y-components:
Solving for β:
β=28.43°
With this angle, the velocity would be:
Vb = 4.2*cos(28.43°) = 3.69m/s
And the time it would take it to cross:
t = 500/3.69 = 135.5s