What does doubling the voltage do to the strength of the electromagnet?

Which statement correctly describes a hypothesis?

tankabanditka [31]

Answer:

D

Explanation:

A hypothesis is pretty much what you think something is, what you think the solution is, with the little information that you already have. this can go on to be tested

7 0

3 years ago

You have two identical pure silver ingots. You place one of them in a glass of water and observe it to sink to the bottom. You p

Elis [28]

Answer: a)

Explanation:

The buoyant force, as stated by Archimedes’ principle, is equal to the weight of the liquid that occupies the same volumen as the submerged object, as follows:

Fb = δ.V.g

If this force is larger than the weight of the object (that means that the fluid is denser than the solid), the object floats, which is the case for silver and mercury.

Instead, silver density is larger than water density, which explains why the pure silver ingot sinks.

Finally, as mercury is denser than water, we conclude that for a same object, the buoyant force in mercury is larger than in water (exactly 13.6 times greater).

3 0

3 years ago

Someone please help me with finding the resistance of these circuits! I've been asking for an hour now. I will give brainliest i

vivado [14]

Answer:

1. 59 Ω

2. 3 Ω

3. 0.625 kΩ

Explanation:

1. The total resistance in a series circuit is equal to the sum of the resistance.

$R_T=R_1+R_2+R_3...\\R_T=20+19+20\\R_T=59$

Therefore, the total resistance in the first circuit is 59 Ω.

2. The total resistance in a parallel circuit is equal to the sum of the reciprocals of the resistance.

$\frac{1}{R_T} = \frac{1}{R_1} +\frac{1}{R_2} +\frac{1}{R_3} ...\\\frac{1}{R_T} = \frac{1}{6.0} +\frac{1}{12} +\frac{1}{36}+\frac{1}{18} \\\frac{1}{R_T} = \frac{1}{3} \\R_T=3$

Therefore, the total resistance in the second circuit is 3 Ω.

3. This is another parallel circuit, so we use the same equation from above:

$\frac{1}{R_T} = \frac{1}{R_1} +\frac{1}{R_2} +\frac{1}{R_3} ...\\\frac{1}{R_T} = \frac{1}{10} +\frac{1}{2} +\frac{1}{1} ...\\\frac{1}{R_T} =1.6\\R_T=\frac{1}{1.6}$

Therefore, the total resistance in the third circuit is $\frac{1}{1.6}$ kΩ, or 0.625 kΩ.

I hope this helps!

8 0

3 years ago

If 2.0 j of work Is done raising a 180 g Apple how far was it lifted

andrew11 [14]

The apple is lifted by 1.1 m

<u>Explanation</u>:

Given that, mgh = 2 J and mass of apple = 180g
Step 1: convert grams to kg as work is given in SI units.

180 g = 0.18 kg

Step 2: substitute in the formula for work done.

0.18 * 10 * h = 2

Step 3: calculate the value of h from this formula.

h = 2/1.8

h = 1.11 m

6 0

3 years ago

3. In a physics lab, 0.500-kg cart (Cart A) moving rightward with a speed of 100 m/s collides with a 1.50-kg cart (Cart B) movin

Alex787 [66]

Answer:

The speed of the two carts after the collision is 10 m/s.

Explanation:

Hi there!

The momentum of the system Cart A - Cart B is conserved because there is no external force acting on the system at the instant of the collision. Then, the momentum of the system before the collision will be equal to the momentum of the system after the collision. The momentum of the system is calculated as the sum of momenta of cart A and cart B:

initial momentum = mA · vA1 + mB · vB1

final momentum = (mA + mB) · vAB2

Where:

mA = mass of cart A = 0.500 kg

vA1 = velocity of cart A before the collision = 100 m/s

mB = mass of cart B = 1.50 kg.

vB1 = velocity of cart B before the collision = - 20 m/s

vAB2 = velocity of the carts that move as a single object = unknown.

(notice that we have considered leftward as negative direction)

Since the momentum of system remains constant:

initial momentum = final momentum

mA · vA1 + mB · vB1 = (mA + mB) · vAB2

Solving for vAB2:

(mA · vA1 + mB · vB1) / (mA + mB) = vAB2

(0.500 kg · 100 m/s - 1.50 kg · 20 m/s) / (0.500 kg + 1.50 kg) = vAB2

vAB2 = 10 m/s

The speed of the two carts after the collision is 10 m/s.

6 0

3 years ago