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3 years ago

8

The equation for the line that passes (-1,-2) and (4,3)

1 answer:

laila [671]3 years ago

5 0

Find the slope and use one point to write the equation of a line (we’ll be using point-slope form). The slope is:
(3 - (-2) ) / (4 - (-1) ) = 1. Plug it into point slope form, y - y1 = m(x - x1), and we get y - 3 = 1(x - 4). If we want to get slope-intercept, distribute the 1, and solve for y: y = x - 1.

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USPshnik [31]

Answer:

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Step-by-step explanation:

Complex numbers identity:

The complex numbers identity is:

$i^2 = -1$

Square of the sum:

$(x + y)^2 = x^2 + 2xy + y^2$

In this question:

$(x + (3+5i))^2$

$x^2 + 2x(3+5i) + (3+5i)^2$

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$x^2 + 6x + (10x+30)i - 16$

So

$(x + (3+5i))^2 = x^2 + 6x + (10x+30)i - 16$

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Answer:

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Step-by-step explanation:

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