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I am Lyosha [343]
3 years ago
10

Distributiv property of 2x(7+4)

Mathematics
1 answer:
natima [27]3 years ago
8 0

Answer: 18

Step-by-step explanation:

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Can someone please help I will give brainliest!!! It’s due tonight
vovangra [49]

Answer:

1738

Step-by-step explanation:

ya I honestly think that the binomial of the quadriceps and triceratops are

3 0
3 years ago
Write the equation of the line that passes through (4,2) and is parallel to the line y=2x-1
Mariulka [41]

Answer: y = 2x-6

Step-by-step explanation:

So we need to write the equation of a line parallel to y=2x-1.

In parallel lines, the slope is the same, so in our new line the slope will be 2x.

We have the equation y = 2x right now. Let's plug in (4,2) for (x,y) and see if it works out, since it must pass through that point.  

y = 2x

2 = 2 * 4

2 doesn't equal 8.  

But if we subtract 6 from the right side of the equation -

y = 2x-6

then it checks out

2 = 2 (4) - 6

2 = 8 - 6

2 = 2

8 0
4 years ago
Read 2 more answers
How to convert the equation<br><img src="https://tex.z-dn.net/?f=y%20%3D%20%20%5Cfrac%7Bq%7D%7B5%20%7B%7D%5E%7Bx%7D%20%7D%20" id
polet [3.4K]

Answer:

xlog 5 = logq - log y\\

Step-by-step explanation:

Given the equation y = \frac{q}{5^{x} }, to convert to linear form, the following steps must be followed;

5^{x} = \frac{q}{y}\\  y5^{x}  = q\\taking\ the\ log\ of\ both\ sides\\log(y5^{x}) = log q\\logy + log 5^{x} = log q\\log y + xlog5 = log q\\xlog 5 = logq - log y\\

The final expression is a linear form of the expression

8 0
4 years ago
Solve this equation 2cos^2x-9cosx-5=0
Nesterboy [21]
2 (n π - i tanh^(-1)(sqrt(2/3))) should be the answer
6 0
3 years ago
How do you make an exponential equation with these two points: (1,2) and (0.5,4)
Over [174]

The required  equation is y=8×(( \frac{1}{2} )^{x}

Step-by-step explanation:

Given,

The two points are (1,2) and (0.5,4)

To find the exponential equation of these given points.

Formula

The general form of exponential equation is y = ab^{x} where, A and B are any real number.

\frac{x^{m} }{x^{n} } = x^{m-n}

Now, the points satisfy the equation.

So,

2 = ab^{1} ------- (1) and

4 =  ab^{0.5} ------ (2)

Now (1) ÷ (2) we get,

\frac{ab }{ab^{0.5} } = \frac{2}{4}

or, b^{0.5} = \frac{1}{2}

or, b = \frac{1}{4} [ by squaring we get]

Now, from (1) we get,

2 = a×\frac{1}{4}

or, a = 8

Hence,

The equation is y=8×(( \frac{1}{2} )^{x}

4 0
3 years ago
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