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In-s [12.5K]
3 years ago
14

(4,2) graph the vertex

Mathematics
1 answer:
ipn [44]3 years ago
3 0

Answer:

To plot (4,2) start at the origin (0,0) and move right 4 units and up 2 units (4,2)

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What are the solutions to the equation (2x - 5) (3x - 1) = 0
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Answer:

x = 5/2 & x = 1/3

Step-by-step explanation:

Create two equations and solve

1) 2x-5 = 0 & 2) 3x-1 = 0

1) 2x = 5

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2) 3x = 1

x = 1/3

You create two equations as you want the left hand side (LHS) to equal 0 (RHS), thus if one of the brackets becomes 0 it will result in the whole LHS beocming 0 as the brackets are being multiplied (anything multiplied by 0 = 0)

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Read 2 more answers
PLEASE HHELP!!! Bring the fraction:
Anna35 [415]

Answer:

\frac{b}{7a^2c} = \frac{5abc^2}{35a^3c^3}

\frac{a}{a - 4} = \frac{-a^2 - 4a}{16 -a^2}

Step-by-step explanation:

Given

\frac{b}{7a^2c}

Express the denominator as 35a^3c^3

To do this, we divide35a^3c^3 by the denominator

\frac{35a^3c^3}{7a^2c} = 5ac^2

So, the required fraction is:

\frac{b}{7a^2c} * \frac{5ac^2}{5ac^2}

\frac{5abc^2}{35a^3c^3}

Hence:

\frac{b}{7a^2c} = \frac{5abc^2}{35a^3c^3}

Given

\frac{a}{a - 4}

Express the denominator as 16 - a^2

Multiply the fraction a+4/a+4

So, we have:

\frac{a}{a - 4} * \frac{(a + 4)}{(a + 4)}

Apply difference of two squares to the denominator

\frac{a^2 + 4a}{a^2 - 16}

Take the additive inverse of the numerator and denominator

\frac{-(a^2 + 4a)}{-(a^2 - 16)}

\frac{-a^2 - 4a}{16 -a^2}

Hence:

\frac{a}{a - 4} = \frac{-a^2 - 4a}{16 -a^2}

8 0
2 years ago
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