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aliina [53]
4 years ago
15

By switching service providers, a family's monthly bill decreased from $57 in May to $35 in June. The monthly bill from May to J

une decreased by ________%? Percent decrease is same as relative change
Mathematics
1 answer:
Zolol [24]4 years ago
7 0
=38.59649123%
=38.6%, cor to 3sf
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Please help I don't understand
aniked [119]

Answer:

The expression can be written as:

5(2) + 6(3) + 2(4).

if I'm wrong, please tell me

5 0
3 years ago
Woody and Jen were paid $60 to paint the garage. Jim started at 8 a.M. And Woody didn't arrive until 10 a.M. The work was comple
Dennis_Churaev [7]

Answer:

$36

Step-by-step explanation:

Jim worked from 8am - 2 pm , which is 6 hours

Woody worked form 10am - 2pm, which is 4 hours

If we take the total time (4+6 = 10) and divide the amount they got, we have:

$60/10 = $6 per hour worked

Since Jim worked 6 hours, he will be paid 6 * 6 = $36

The rest, 60 - 36 = $24 would be paid to Woody (he worked less).

Jim's fair share of earning is $36

8 0
4 years ago
Look at the graph. What is ?
shepuryov [24]

Answer:

no picture.

Step-by-step explanation:

no picture

4 0
3 years ago
Decide which part of the quadratic formula tells you whether the quadratic equation can be solved by factoring:
andre [41]
The part of the quadratic formula that dictates whether the function is factorable or not is B. b^2 - 4ac. This determines the number of real, imaginary, negative and positive roots. 
In the equation <span>2x^2 + 7x + 3, 
we use the quadratic formula 
x = -b +- sqrt (b2 -4ac) /2a = -7 +- </span><span>sqrt (49 -24) /4
the answers are x1 =-0.5 and x2 = -3.</span>
4 0
3 years ago
Read 2 more answers
Im confused..I feel as if what I’m learning in class itself is not as difficult as the problems my teacher gives us to take home
RideAnS [48]
Ok, so remember that the derivitive of the position function is the velocty function and the derivitive of the velocity function is the accceleration function

x(t) is the positon function
so just take the derivitive of 3t/π +cos(t) twice
first derivitive is 3/π-sin(t)
2nd derivitive is -cos(t)
a(t)=-cos(t)

on the interval [π/2,5π/2) where does -cos(t)=1? or where does cos(t)=-1?
at t=π
so now plug that in for t in the position function to find the position at time t=π
x(π)=3(π)/π+cos(π)
x(π)=3-1
x(π)=2
so the position is 2







ok, that graph is the first derivitive of f(x)
the function f(x) is increaseing when the slope is positive
it is concave up when the 2nd derivitive of f(x) is positive

we are given f'(x), the derivitive of f(x)
we want to find where it is increasing AND where it is concave down

it is increasing when the derivitive is positive, so just find where the graph is positive (that's about from -2 to 4)

it is concave down when the second derivitive (aka derivitive of the first derivitive aka slope of the first derivitive) is negative
where is the slope negative?
from about x=0 to x=2
and that's in our range of being increasing
so the interval is (0,2)
4 0
4 years ago
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