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3 years ago

15

By switching service providers, a family's monthly bill decreased from $57 in May to $35 in June. The monthly bill from May to J

une decreased by ________%? Percent decrease is same as relative change

1 answer:

Zolol [24]3 years ago

7 0

=38.59649123%
=38.6%, cor to 3sf

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Solve the system: (MAFS.912-A-REI.3.6)

faust18 [17]

Step-by-step explanation:

$4x + 7y = 41 \\ 4 \times ( - 7) + 7 \times ( - 16) = 41$

7 0

3 years ago

Which of the following represents the factorization of the trinomal below

Ira Lisetskai [31]

X^2 - x - 20
(x + 4)(x - 5) <==

x^2 - x - 20.....the last sign, which is negative, tells me that one set is positive and one set is negative. The first sign, which is also negative, tells me that the larger number will be negative. Now u have to find 2 numbers, that when added equal -1 and when multiplied, equal -20....those numbers are -5 and 4. so ur answer is : (x + 4)(x - 5)

3 0

3 years ago

Read 2 more answers

Henry makes $7.00 per hour before taxes working at a movie theater. On Tuesday, Henry worked 5 hours, and then he worked 4 hours

olganol [36]

Answer:

Step-by-step explanation:

1hr = $7.00

Therefore,

5 + 4 x 7

= $63

DV = Hours of work.

7 0

3 years ago

Evaluate the surface integral. ??s (x2 y2 z2 ds s is the part of the cylinder x2 y2 = 4 that lies between the planes z = 0 and z

kondor19780726 [428]

The surface $S$ can be parameterized by

$\mathbf r(\theta,z)=(2\cos\theta,2\sin\theta,z)$

where $0\le\theta\le2\pi$ and $0\le z\le2$ . Then the surface integral can be computed with

$\displaystyle\iint_S(x^2+y^2+z^2)\,\mathrm dS$
$\displaystyle=\int_{\theta=0}^{\theta=2\pi}\int_{z=0}^{z=2}(4\cos^2\theta+4\sin^2\theta+z^2)\|\mathbf r_\theta\times\mathbf r_z\|\,\mathrm dz\,\mathrm d\theta=\dfrac{128\pi}3$

6 0

3 years ago

The roots of an equation are x=-1 plus or minus I the equation is x^2+ ?

Oxana [17]

Answer:

x^2+2x+2

Step-by-step explanation:

If the roots of the equation are -1\pm i, then by the zero product rule:

$x=-1\pm i \\\\x+1\pm i=0 \\\\(x+1+i)(x+1-i)=0\\\\x^2+x-ix+x+1-i+ix+i+1=0 \\\\x^2+2x+2=0$

You can confirm this with the quadratic equation:

$x=\dfrac{-2\pm\sqrt{4-8}}{2}=\dfrac{-2\pm 4i}{2}=-1\pm i$

Hope this helps!

8 0

3 years ago