307 g of an unknown mineral is heated to 98.7 °C and placed into a calorimeter that contains 72.4 g of water at 23.6 °C. The hea
1 answer:
Answer:
0.138 J/g.K
Explanation:
According to the law of conservation of energy, the sum of the heat released bt he mineral and the heats absorbed by the water and the calorimeter is equal to zero.
Qm + Qw + Qc = 0
Qm = - Qw - Qc [1]
The heat absorbed by the calorimeter can be calculated using the following expression.
Q = C . ΔT
where,
C is the heat capacity
ΔT is the change in temperature
The heat released by the mineral and the one absorbed by the water can be calculated using the following expression.
Q = c . m . ΔT
where,
c is the specific heat capacity
m is the mass
ΔT is the change in temperature
Replacing in [1],
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Answer:
U-238
Explanation:
For a given radioisotope, half life can be defined as the time taken for the isotope to decay into one-half of its original amount. Mathematically, this is expressed as:
where k = rate constant for the radioactive decay process
Greater the t1/2 longer will be its stability.
Based on the given data, U-238 has the largest half life and therefore will be best suited for applications mentioned.