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Drupady [299]
3 years ago
6

I need to fix the equations

Chemistry
1 answer:
marishachu [46]3 years ago
3 0

Answer:

try looking the equations or find a calulator for those type of eqautions

Explanation:

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8 0
3 years ago
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Sodium and chlorine react to form sodium chloride. If there are 1.4 moles of sodium used, how many moles of chlorine were requir
sammy [17]

Answer:

0.7 moles of Chlorine gas is required.

Explanation:

The reaction is balanced as follows:

2Na + Cl_{2} ------>  2NaCl

According to stoichiometry,

2 mole Sodium reacts with 1 mole Chlorine gas

∴1 mole Sodium reacts with 1/2 moles of Chlorine gas

∴1.4 mole sodium reacts with 1.4/2 moles of Chlorine gas

                                                = 0.7 moles of Chlorine gas

So, 0.7 moles of Chlorine gas is required.

3 0
3 years ago
If the pressure of a gas is 1.50 atm, its volume is 2.50 L, and its temperature is 22, what is the volume if the pressure is inc
aksik [14]

Answer:

The answer to your question is V2 = 1.3 l

Explanation:

Data

Pressure 1 = P1 = 1.5 atm

Volume 1 = V1 = 2.50 l

Temperature 1 = T1 = 22°C

Pressure 2 = P2 = 3 atm

Volume 2 = V2 = ?

Temperature 2 = T2 = 35°C

Process

1.- Convert temperature to °K

T1 = 22 + 273 = 295°K

T2 = 35 + 273 = 308°K

2.- Use the combine gas law to solve this problem

                P1V1/T1 = P2V2/T2

-Solve for V2

                V2 = P1V1T2 / T1P2

3.- Substitution

                V2 = (1.5 x 2.5 x 308) / (295 x 3)

4.- Simplification

                V2 = 1155 / 885

5.- Result

                 V2 = 1.3 l

3 0
4 years ago
Draw an atomic structure of Sodium (Na). What are sub-atomic particles?​
xxMikexx [17]

Sodium represents by the (Na).

7 0
2 years ago
Calculate the mass of 1.0 L of helium (He), 1.0 L of chlorine gas (Cl2), and 1.0 L of air (79% N2, 21% O2 by volume) at 25°C and
Zigmanuir [339]

To calculate the mass we use the following formulas:

PV=nRT     (1)

and

n = m / M    (2)

where:

P - pressure (atm)

V - volume (L)

n - moles

R - gas constant = 0.082 (L × atm) / (mol × K)

T - temperature (°K) (25°C + 273 = 298°K)

m - mass (g)

M - molecular mass (g/mole)

Now we rewrite equation (1):

n = PV / RT

And replace n with m / M from equation (2):

m / M = PV / RT

m = (P × V × M) / (R ×T)

1 L of He will have a mass of:

m = (1 × 1 × 4) / (0.082 × 298) = 0.1637 g

1 L of Cl₂ will have a mass of:

m = (1 × 1 × 71) / (0.082 × 298) = 2.9055 g

1.0 L of air will contain 0.79 L of N₂ and 0.21 L of O₂

0.79 L of N₂ will have a mass of:

m = (1 × 0.79 × 28) / (0.082 × 298) = 0.9052 g

0.21 L of O₂ will have a mass of:

m = (1 × 0.21 × 32) / (0.082 × 298) = 0.2750 g

mass of air = mass of N₂ + mass of O₂

mass of air = 0.9052 + 0.2750 = 1.1802 g

A balloon filed with helium will rise because as you see 1 L of helium is lighter than 1 L of air.

Chlorine gas is dangerous because chlorine is very toxic for human life and more of that is heavier than the air so will diffuse very hard from the area where the leak appeared.

7 0
4 years ago
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