337.92 moles of Ozone will be produced
1 Oxygen atom is 8 g
1 mole of ozone, O3 = 8 * 3 = 24 g
7.92 * 1024 = 8110.08 g
1 mole = 24 g
? moles = 8110.08 g
? = 337.92 moles
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Answer:
C and D
C. There must be 80- 100 inches per year
D. No rain must be distributed throughout the year ;)
Explanation:
Answer:
15.0 g
Explanation:
Step 1: Given and required data
- Heat used to melt a sample of ice (Q): 5.01 kJ
- Latent heat of fusion of water (ΔH°fus): 334 kJ/kg
Step 2: Calculate the mass (m) of water
334 kJ are required to melt 1 kg of ice at 0°C (melting point of water). We can calculate the mass of ice melted by 5.01 kJ using the following expression.
<em>Q = ΔH°fus × m</em>
m = Q / ΔH°fus
m = 5.01 kJ / (334 kJ/kg)
m = 0.0150 kg = 15.0 g
Answer:
ionic solute surrounded by polar solvent
Explanation:
In the process of solvation the polar solute ions are surrounded by the polar dipoles of the solvent molecule. For example when NaCl dissolves in water the Na⁺ cation is surrounded by the partially negatively charged O atoms of water molecules. Similarly, Cl⁻ anion is surrounded by the partially positively charged H atoms of water molecules.