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2 years ago

13

Find the values of x and y.

1 answer:

malfutka [58]2 years ago

4 0

Answer:

y=57, x=77

Step-by-step explanation:

The line that creates x-3 is parrelell to the line that makes 74 degrees

You know that x-3=74

When you simplify you get x=77

Now that you know that x-3=74 you can add all the angles to 180 because they are a supplementary angle

74+41+(y+8)=180, then simplify

115+y+8=180, simplify more

123+y=180

y=57

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Answer the question above on the ixl tab, please.

kramer

Answer:

<h2>The answer is 10</h2>

Step-by-step explanation:

The formula for finding the combination of two given positive numbers is given by

<h3> $_{n}C _{r} = \frac{n!}{(n - r)!r!}$ </h3>

Where n and r are positive numbers

From the question we have

5 C 3

<u>Simplify</u>

That's

<h3> $\binom{5}{3} = \frac{5!}{(5 - 3)!3!} = \frac{120}{2! \times 3 !} \\ = \frac{120}{2 \times 6} \\ = \frac{120}{12}$ </h3>

We have the final answer as

<h3>10</h3>

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2 years ago

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Answer:

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3 years ago

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3 years ago

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2 years ago

Read 2 more answers

Find the angle between the given vectors. Round your answer, in degrees, to two decimal places. u=⟨2,−6⟩u=⟨2,−6⟩, v=⟨4,−7⟩

NISA [10]

Answer:

$\theta = 108.29$

Step-by-step explanation:

Given

$u =$

$v =$

Required:

Calculate the angle between u and v

The angle $\theta$ is calculated as thus:

$cos\theta = \frac{u.v}{|u|.|v|}$

For a vector

$A =$

$A = a * b$

$cos\theta = \frac{u.v}{|u|.|v|}$ becomes

$cos\theta = \frac{.}{|u|.|v|}$

$cos\theta = \frac{2*6+4*-7}{|u|.|v|}$

$cos\theta = \frac{12-28}{|u|.|v|}$

$cos\theta = \frac{-16}{|u|.|v|}$

For a vector

$A =$

$|A| = \sqrt{a^2 + b^2}$

So;

$|u| = \sqrt{2^2 + 6^2}$

$|u| = \sqrt{4 + 36}$

$|u| = \sqrt{40}$

$|v| = \sqrt{4^2+(-7)^2}$

$|v| = \sqrt{16+49}$

$|v| = \sqrt{65}$

So:

$cos\theta = \frac{-16}{|u|.|v|}$

$cos\theta = \frac{-16}{\sqrt{40}*\sqrt{65}}$

$cos\theta = \frac{-16}{\sqrt{2600}}$

$cos\theta = \frac{-16}{\sqrt{100*26}}$

$cos\theta = \frac{-16}{10\sqrt{26}}$

$cos\theta = \frac{-8}{5\sqrt{26}}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{-8}{5\sqrt{26}})$

$\theta = cos^{-1}(\frac{-8}{5 * 5.0990})$

$\theta = cos^{-1}(\frac{-8}{25.495})$

$\theta = cos^{-1}(-0.31378701706)$

$\theta = 108.288386087$

<em></em> $\theta = 108.29$ <em> (approximated)</em>

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2 years ago