All categories

2 years ago

The volume of a cylinder is 768 N in³. Find the radius of the cylinder (in inches) if the height is 3 in

1 answer:

6 0

To find the volume of the cylinder we multiply the area of the face by the height of the cylinder. Area pi*r^2
First find area
768in^3/3in = 256in^2
Pi*r^2 = 256
r^2 = 256 / pi
radius = root of 256/pi
Hence radius = 9.027033337 in
To check answer
Pi*9.027033337^2 * 3in = 768in^3

Finalized answer to 2 d.p
Radius = 9.03 in

You might be interested in

Which sequence of transformations will change figure PQRS to figure P′Q′R′S′?

masya89 [10]

Answer:

Counterclockwise rotation about the origin by 90 degrees followed by reflection about the y-axis .

Step-by-step explanation:

The shape is moved to the opposite quadrant of the second shape then flied directly onto the second shape.

3 0

2 years ago

Read 2 more answers

Solve the following equation:

Rama09 [41]

Complete the square.

$z^4 + z^2 - i\sqrt 3 = \left(z^2 + \dfrac12\right)^2 - \dfrac14 - i\sqrt3 = 0$

$\left(z^2 + \dfrac12\right)^2 = \dfrac{1 + 4\sqrt3\,i}4$

Use de Moivre's theorem to compute the square roots of the right side.

$w = \dfrac{1 + 4\sqrt3\,i}4 = \dfrac74 \exp\left(i \tan^{-1}(4\sqrt3)\right)$

$\implies w^{1/2} = \pm \dfrac{\sqrt7}2 \exp\left(\dfrac i2 \tan^{-1}(4\sqrt3)\right) = \pm \dfrac{2+\sqrt3\,i}2$

Now, taking square roots on both sides, we have

$z^2 + \dfrac12 = \pm w^{1/2}$

$z^2 = \dfrac{1+\sqrt3\,i}2 \text{ or } z^2 = -\dfrac{3+\sqrt3\,i}2$

Use de Moivre's theorem again to take square roots on both sides.

$w_1 = \dfrac{1+\sqrt3\,i}2 = \exp\left(i\dfrac\pi3\right)$

$\implies z = {w_1}^{1/2} = \pm \exp\left(i\dfrac\pi6\right) = \boxed{\pm \dfrac{\sqrt3 + i}2}$

$w_2 = -\dfrac{3+\sqrt3\,i}2 = \sqrt3 \, \exp\left(-i \dfrac{5\pi}6\right)$

$\implies z = {w_2}^{1/2} = \boxed{\pm \sqrt[4]{3} \, \exp\left(-i\dfrac{5\pi}{12}\right)}$

3 0

1 year ago

Does the point (10, 13) satisfy the equation y = x?

Trava [24]

Equation: y = x

When x = 10, y = 10

----------------------------------------------------------------------------
Answer: No, (10, 13) does not satisfy the equation y = x.
---------------------------------------------------------------------------

7 0

3 years ago

Read 2 more answers

If abc is parallel to dec=55 cde=65 and abc=2x

MrMuchimi

Answer:

Step-by-step explanation:

ye4ayea

3 0

2 years ago

Please help help help meee

Allisa [31]

Answer:

Kaylaa do you use desmos graphing calculator? it's an online graphsing tool and would make this very easy for you. Maybe you are not allowed to use a calculator?

Step-by-step explanation:

with out a calculator it's a long math process, 1st because each of the equations are equal to Y, we can set each of them equal to each other. like this

$\sqrt{x-8}$ + 3 = - $(x-5)^{2}$ + 18