Answer:
Dang, You still waiting?
Step-by-step explanation:
I need help with things to T~T
4000
yeah i just need the points here
Let us assume the number of hours after which the cost of Pam and Michelle will be same = x
Now let us concentrate on the information's already given in the problem.
Fixed charge taken by Pam = $125
Charge per hour taken by Pam = $15
Fixed charge taken by Michelle = $50
Charge per hour taken by Michelle = $20
Then
125 + 15x = 50 + 20x
20x - 15x = 125 - 50
5x = 75
x = 75/5
= 15
So after 15 hours the charge taken by Pam and Michelle will be the same. I hope the procedure for doing this type of problem is clear to you.
Let Ted be x.
Ed is 7 years older = x + 7
Ed = (3/4)Ted
(x + 7) = (3/4)x
x + 7 = 3x/4
x - 3x/4 = -7
x/4 = -7
x = -28, Ted = -28 years.
(x + 7) = -28 + 7 = -21, Ed = -21 years
Goodness. We had negative numbers for the ages, well does that make sense? No it doesn't.
Our answer is correct. But the sense in the question is lacking. The question has been wrongly set.
<span>We might assume negative ages to mean before they came into the world, before birth! </span>
1.Simplify.
-2{x}^{2}-4x+13+12{x}^{2}+2x-25−2x2−4x+13+12x2+2x−25
2.Collect like terms.
(-2{x}^{2}+12{x}^{2})+(-4x+2x)+(13-25)(−2x2+12x2)+(−4x+2x)+(13−25)
3.Simplify.
10{x}^{2}-2x-1210x2−2x−12
