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3 years ago

Identify the slope that goes through the two given coordinates (-3,0) (3,2)???

Mathematics

1 answer:

katrin [286]3 years ago

8 0

when solving for slope use the equation M=y2-y1/x2-x1

this is how you would set it up:

1.) set out your Ys and Xs:

Y2= 2 Y1= 0 X2= 3 X1= -3

2.) set up your equation:

M= Y2-Y1/ X2-X1

M= 2-(0)/3-(-3)

M= 2/6

M= 1/3

3.) your answer is:

M= 1/3

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Just number 7 would be fine but if you could also number 8 would help a lot

BlackZzzverrR [31]

Answer:

7. r = -5

8. x = -1

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Step-by-step explanation:

Step 1: Define

r + 2 - 8r = -3 - 8r

Step 2: Solve for r

Combine like terms: -7r + 2 = -3 - 8r
Add 8r to both sides: r + 2 = -3
Subtract 2 on both sides: r = -5

Step 3: Check

Plug in r into the original equation to verify it's a solution.

Substitute in r: -5 + 2 - 8(-5) = -3 - 8(-5)
Multiply: -5 + 2 + 40 = -3 + 40
Add: -3 + 40 = -3 + 40
Add: 37 = 37

Here we see that 37 does indeed equal 37.

∴ r = -5 is a solution of the equation.

Step 4: Define equation

-4x = x + 5

Step 5: Solve for x

Subtract x on both sides: -5x = 5
Divide -5 on both sides: x = -1

Step 6: Check

Plug in x into the original equation to verify it's a solution.

Substitute in x: -4(-1) = -1 + 5
Multiply: 4 = -1 + 5
Add: 4 = 4

Here we see that 4 does indeed equal 4.

∴ x = -1 is a solution of the equation.

8 0

3 years ago

Read 2 more answers

(5÷3)x+(1÷2)=0 find x

xxMikexx [17]

(1.6666667)x+(.5)=0
1.6666667x=-.5
1.6666667x/1.666667=-.5/1.6666667
x= -.5/1.6666667
x=.3

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4 years ago

I need help please :)

padilas [110]

Answer:

what the heck is that hard math what grade are you even in?

Step-by-step explanation:

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3 years ago

Which type of transformation to the triangle has occurred from graph 1 to graph 2 in this diagram

mel-nik [20]

Answer:

B. Rotation

Step-by-step explanation:

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3 years ago

Does anyone know the answer to this one?

polet [3.4K]

Answer:

$\large\boxed{a(x+4)(x-5)=0,\ a\in\mathbb{R}-\{0\}}\\\\\text{for}\ a=1\to\boxed{x^2-x-20=0}$

Step-by-step explanation:

$\text{If}\ x_1\ \text{and}\ x_2\ \text{are the roots of the quadratic equation}\ ax^2+bx+c=0,\\\text{then}\ ax^2+bx+c=a(x-x_1)(x-x_2).\\\\\text{If}\ x_1\ \text{and}\ x_2\ \text{, then they are the roots of the quadratic equation.}\\\\\text{We have}\ x_1=-4\ \text{and}\ x_2=5.\ \text{Therefore we have the equation:}\\\\a(x-(-4))(x-5)=0\\\\a(x+4)(x-5)=0\qquad\text{for any value of}\ a\ \text{except 0}.$

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4 years ago