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3 years ago

If m<3 =54°. find each measure.

Mathematics

1 answer:

weqwewe [10]3 years ago

6 0

Answer/Step-by-step explanation:

Given:

m<3 = 54°

m<2 = right angle

a. m<1 + m<2 + m<3 = 180° (angles in a straight line)

m<1 + 90° + 54° = 180° (substitution)

m<1 + 144° = 180°

m<1 = 180° - 144°

m<1 = 36°

b. m<2 = 90° (right angle)

c. m<4 = m<1 (vertical angles)

m<4 = 36° (substitution)

d. m<5 = m<2 (vertical angles)

m<5 = 90°

e. m<6 = m<3 (vertical angles)

m<6 = 54°

f. m<7 + m<6 = 180° (same side interior angles)

m<7 + 54° = 180° (substitution)

m<7 = 180 - 54

m<7 = 126°

g. m<8 = m<6 (alternate interior angles are congruent)

m<8 = 54°

h. m<9 = m<7 (vertical angles)

m<9 = 126°

i. m<10 = m<8 (vertical angles)

m<10 = 54°

j. m<11 = m<4 (alternate interior angles are congruent)

m<11 = 36° (substitution)

k. m<12 + m<11 = 180° (linear pair)

m<12 + 36° = 180° (substitution)

m<12 = 180° - 36°

m<12 = 144°

l. m<13 = m<11 (vertical angles)

m<13 = 36°

m. m<14 = m<12 (vertical angles)

m<14 = 144° (substitution)

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$(f \circ g)(x) = x+12$

Domain = [-3, infinity)

==================================================

Work Shown:

$f(x) = x^2 + 9\\\\f(g(x)) = (g(x))^2 + 9\\\\f(g(x)) = (\sqrt{x+3})^2 + 9\\\\f(g(x)) = x+3 + 9\\\\f(g(x)) = x+12\\\\(f \circ g)(x) = x+12\\\\$

In step 2, we replaced every x with g(x)

In step 3, we plugged in g(x) = sqrt(x+3)

The domain of g(x) is [-3, infinity), so this is the domain of $(f \circ g)(x)$ as well since the composite function depends entirely on g(x). Put another way: the input of f(x) depends on the output of g(x), so that's why the domains match up.

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Step-by-step explanation:

There is really no need to use any quadratics or roots.

( Consider the same problem on the plain number line first. )

How do you find the number between 2 and 5 which is twice as far from 2 as from 5?

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