All categories

3 years ago

Find the lengths of the missing sides. If the length is irrational, round to the nearest tenth.

Mathematics

2 answers:

grigory [225]3 years ago

8 0

Answer: 25

Step-by-step explanation:

Yuri [45]3 years ago

8 0

25in
Using Pythagorean theorem (a^2+b^2=c^2)
15^2+20^2=c^2
225+400=c^2
625=c^2
Square root to get c alone
C=25

You might be interested in

I need help or I’m going to fail math

gavmur [86]

Answer:

1. A

2. B

3. D

Step-by-step explanation:

Use PEMDAS to solve all

8^2 - 6*2

8*8 - 6*2

64 - 12 = 52

4^2 * 3 + 4 * 2

4 * 4 * 3 + 4 * 2

16 * 3 + 8

48 + 8 = 56

9^2 - 2(5+3)

9 * 9 - 2(8)

81 - 16 =65

4 0

2 years ago

Solve <br><br> 0.6(10n + 25) = 10 + 5n ?

Pachacha [2.7K]

Answer: $x=-5$

<u>Simplify both sides of the equation</u>

$(0.6)(10n)+(0.6)(25)=10+5n(Distribute)\\6n+15=10+5n\\6n+15=5n+10$

<u>Subtract 5n from both sides</u>

$6n+15-5n=5n+10-5n\\n+15=10$

<u>Subtract 15 from both sides</u>

$n+15-15=10-15\\n=-5$

5 0

4 years ago

Read 2 more answers

48 is 9 less than 3 times a number. What is the number?

Kamila [148]

19 x 3 = 57 57 - 9 = 48 Your answer is 19.

4 0

4 years ago

Read 2 more answers

Gerald has a punch bowl in the shape of a hemisphere as shown below.

zmey [24]

The closest to the maximum number of cups the punch bowl can hold is 30

<h3>How to determine the number of cups?</h3>

The given parameters are:

1 cup = 15 cubic inches

Diameter of bowl, d = 12 inches

The radius is the half of the diameter.

So, we have:

r = 6

The volume of the bowl is then calculated using:

$V = \frac{2}{3}\pi r^3$

This gives

$V = \frac{2}{3}\pi * 6^3$

Evaluate

V = 452.16

The maximum number of cups is then calculated using:

Cups = 452.16/15

Evaluate

Cups = 30.1444

Approximate

Cups = 30

Hence, the closest to the maximum number of cups the punch bowl can hold is 30

Find the lengths of the missing sides. If the length is irrational, round to the nearest tenth. ​

Find the lengths of the missing sides. If the length is irrational, round to the nearest tenth.