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18. Using the diagram below as reference, write a paragraph proof to prove that the symmetric property of congruence exists for any two angles. (IMAGE BELOW)
Given: ∠A is congruent to ∠B
Prove: ∠B is congruent to ∠A
Plan: Show that ∠A and ∠B have the same measure, thus ∠B and ∠A have the same measure under symmetry for equality. Conclude with ∠B being congruent to ∠A.
18. Using the diagram below as reference, write a paragraph proof to prove that the symmetric property of congruence exists for any two angles. (IMAGE BELOW)
Given: ∠A is congruent to ∠B
Prove: ∠B is congruent to ∠A
Plan: Show that ∠A and ∠B have the same measure, thus ∠B and ∠A have the same measure under symmetry for equality. Conclude with ∠B being congruent to ∠A.
1 answer:
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Answer:
Step-by-step explanation:
Answer:
a. The amount that is saved at the expiration of the 5 year period is $22,769.20¢
b. The amount of interest is $2,769.20¢
Step-by-step explanation:
Since the amount that is deposited every year for a period of five years is $4,000 and the rate of the interest is 6.5%. We can always calculate the amount that is saved at the expiration of the five years.
We will first state the formula for calculating the future value of annuity:-
Future value of annuity =
Where P is the amount deposited per year.
r is the rate of interest
t is the time or period
and in this case, the actual value of P = $4,000
rate of interest, r is 6.5% = 0.065
time, t is 5 years.
Substituting e, we have:
Fv of annuity =
= 4,000 × [((1.065)^5)- 1/0.065]
= 4,000 × [(1.37 - 1)/0.065]
= 4,000 × (0.37/0.065)
= 4,000 × 5.6923
= $22,769.20¢
a. Therefore the amount that is saved at the end of the five (5) years is $22,769.20¢
b. To find the interest, we will calculate the amount of deposit made during the period of five years and subtract the sum from the current amount that is saved ($22,769.29¢).
Since I deposited 4,000 every year for five years, the total amount of deposit I made at the period =
4,000 × 5 = $20,000
The amount of interest is then = $22,769.20¢ - $20,000 = $2,769.20¢
The y values from:
1. ₋6
2. ₋3
3. 0
4. 3
Given the x values and y value as y = 3x
1. when x = ₋2 then y = 3x
y = 3(₋2)
y = ₋6
2. when x = ₋1 then y = 3x
y = 3(₋1)
y = ₋3
3. when x = 0 then y = 3x
y = 3(0)
y = 0
4. when x = 1 then y = 3x
y = 3(1)
y = 3
therefore we get the points as (₋2 , ₋6) (₋1 , ₋3) (0,0) (1 , 3).The graph is pltted and attached.
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