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butalik [34]
2 years ago
11

A consumer report counted 72 low-quality, 112 medium-quality, and 711 high-quality computers based on a random sample. The repor

t went on to say that all computers, regardless of quality, are packaged identically and sold at the same price.
Use the observed frequencies to create a probability model for the quality of the next computer purchased.
Input your answers as fractions or as decimals rounded to the nearest hundredth.
Mathematics
1 answer:
blsea [12.9K]2 years ago
8 0

Answer:

high quality = 711/895

medium quality = 112/895

low quality = 72/895

Step-by-step explanation:

72 + 112 + 711 = 895

high quality = 711/895

medium quality = 112/895

low quality = 72/895

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How to calculate the three averages for the given data?
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For a data set of weights​ (pounds) and highway fuel consumption amounts​ (mpg) of eight types of​ automobile, the linear correl
Jobisdone [24]

Answer:

The P value indicates that the probability of a linear correlation coefficient that is at least as extreme is 0.3% which is not significant (at α = 0.05), so there is insufficient evidence to conclude that there is a linear correlation between weight and consumption. of highway fuel in cars.

Step-by-step explanation:

We have that the correlation coefficient shows the relationship between the weights and amounts of road fuel consumption of seven types of car, now the P value establishes the importance of this relationship. If the p-value is lower than a significance level (for example, 0.05), then the relationship is said to be significant, otherwise it would not be so, this case being 0.003 not significant.

The statement would be the following:

The P value indicates that the probability of a linear correlation coefficient that is at least as extreme is 0.3% which is not significant (at α = 0.05), so there is insufficient evidence to conclude that there is a linear correlation between weight and consumption. of highway fuel in cars.

5 0
3 years ago
Tatiana is practicing shooting. The coordinates (in m) of the barrel of her gun and the target are (5, 3, 1) and (38, 41, 3). Wh
saul85 [17]

Answer:

d=\sqrt{2,537}\ m   or  d=50.37\ m

Step-by-step explanation:

we know that

the formula to calculate the distance between two points in three dimensions is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}+(z2-z1)^{2}}

Let

A(5,3,1)  -----> coordinates of the barrel of her gun

B(38,41,3)  -----> coordinates of the target

substitute the values

d=\sqrt{(41-3)^{2}+(38-5)^{2}+(3-1)^{2}}

d=\sqrt{(38)^{2}+(33)^{2}+(2)^{2}}

d=\sqrt{1,444+1,089+4}

d=\sqrt{2,537}\ m

d=50.37\ m

7 0
3 years ago
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