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4 years ago

7

Alan makes a fruit salad using strawberries and blueberries. He uses 5 cups of strawberries for every 3 cups of blueberries. Whi

ch measure represents the amount of strawberries Alan uses for every 1 cup of fruit salad? A. 3/8 cup B. 3/5 cup C. 5/8 cup D. 5/3 cup PLEASE HURRY I NEED THIS.

1 answer:

fredd [130]4 years ago

4 0

Answer:

C. 5/8 cup

Step-by-step explanation:

5 + 3 = 8
Strawberries/total amount = 5/8

I hope this helps!

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April worked 1 1/2 times as long on her math project as did Carl. Debbie worked 1 1/4 times as long as Sonia. Richard worked 1 3

vlada-n [284]

Answer:

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

Step-by-step explanation:

Some data's were missing so we have attached the complete information in the attachment.

Given:

Number of Hours Carl worked on Math project = $5\frac{1}{4}\ hrs$

$5\frac{1}{4}\ hrs$ can be Rewritten as $\frac{21}{4}\ hrs$

Number of Hours Carl worked on Math project = $\frac{21}{4}\ hrs$

Number of Hours Sonia worked on Math project = $6\frac{1}{2}\ hrs$

$6\frac{1}{2}\ hrs$ can be rewritten as $\frac{13}{2}\ hrs$

Number of Hours Sonia worked on Math project = $\frac{13}{2}\ hrs$

Number of Hours Tony worked on Math project = $5\frac{2}{3}\ hrs$

$5\frac{2}{3}\ hrs$ can be rewritten as $\frac{17}{3}\ hrs.$

Number of Hours Tony worked on Math project = $\frac{17}{3}\ hrs.$

Now Given:

April worked $1\frac{1}{2}$ times as long on her math project as did Carl.

$1\frac{1}{2}$ can be Rewritten as $\frac{3}{2}$

Number of Hours April worked on math project = $\frac{3}{2}$ $\times$ Number of Hours Carl worked on Math project

Number of Hours April worked on math project = $\frac{3}{2}\times \frac{21}{4} = \frac{63}{8}\ hrs \ \ Or \ \ 7\frac{7}{8} \ hrs$

Also Given:

Debbie worked $1\frac{1}{4}$ times as long as Sonia.

$1\frac{1}{4}$ can be Rewritten as $\frac{5}{4}$ .

Number of Hours Debbie worked on math project = $\frac{5}{4}$ $\times$ Number of Hours Sonia worked on Math project

Number of Hours Debbie worked on math project = $\frac{5}{4}\times \frac{13}{2}= \frac{65}{8}\ hrs \ \ Or \ \ 8\frac{1}{8}\ hrs$

Also Given:

Richard worked $1\frac{3}{8}$ times as long as tony.

$1\frac{3}{8}$ can be Rewritten as $\frac{11}{8}$

Number of Hours Richard worked on math project = $\frac{11}{8}$ $\times$ Number of Hours Tony worked on Math project

Number of Hours Debbie worked on math project = $\frac{11}{8}\times \frac{17}{3}= \frac{187}{24}\ hrs \ \ Or \ \ 7\frac{19}{24}\ hrs$

Hence We will match each student with number of hours she worked.

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

5 0

3 years ago

Read 2 more answers

PLEASE HELP FOR BRAINLIEST ANSWER!!!!!!!!

wel

X = 78 degrees

Explanation:
Using the alternate exterior angle of 33 degrees, the angle to the left of x would also be 33 degrees
Using this we add up 69 and 33 = 102
Then we would do 180-102 since a straight line has a total of 180 degrees
The answer would be 78 degrees

3 0

3 years ago

a recipe for soup calls for 4 3/4 cup of water 1/2 teaspoon of salt, and 2 1/2 cups of mixed vegetables. if the recipe yields tw

tekilochka [14]

All we have to do is multiply by two

4 3/4 * 2 = 9 1/2
1/2 * 2 = 1
2 1/2 * 2 = 5

7 0

3 years ago

What is the End Behavior of the following Graph?

natima [27]

Answer:

b hopefully this helps you with work

5 0

3 years ago

The function, p(d)equals=1plus+startfraction d over 33 endfraction d 33, gives the pressure, in atmospheres (atm), at a dep

Gelneren [198K]

Answer:

The pressure at 50 feet is 2.51515 atm

Step-by-step explanation:

we are given equation as

$p(d)=1+\frac{d}{33}$

where

p(d) gives the pressure, in atmospheres (atm)

a depth d in the sea (d is in feet)

We are given

d=50 feet

So, we can plug d=50 and find p

$p(50)=1+\frac{50}{33}$

$p(50)=2.51515atm$

So,

The pressure at 50 feet is 2.51515 atm

7 0

3 years ago

Read 2 more answers