Answer:- 544.5 mL of water need to be added.
Solution:- It is a dilution problem. The equation used for solving this type of problems is:

where,
is initial molarity and
is the molarity after dilution. Similarly,
is the volume before dilution and
is the volume after dilution.
Let's plug in the values in the equation:



Volume of water added = 907.5mL - 363mL = 544.5 mL
So, 544.5 mL of water are need to be added to the original solution for dilution.
<span>mass percent of carbon (c) in CCl</span>₄ = mass of C/mass of CCl₄
= 12 x 100/153.8 = 7.8%
1) use the formula PV=nRT
2) Plug in given values: P(8.77 L)= (1.45 mol)(0.0821)(293 K)
3) isolate P: P= (1.45x.0821x293)/(8.77)
4) solve: P=3.98 atm
Explanation:
6×1.25×37.5= 281.5 g of chlorine
1×1.25×2= 2.5 g of hydrogen