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ira [324]
4 years ago
5

Which chemical equation is correctly balanced?. . 1) Na + O2  Na2O . . 2) Na + O2  2 Na2O. . 3) 2 Na + 2 O2  2 Na2O. . 4) 4 N

a + O2  2 Na2O.
Chemistry
1 answer:
snow_tiger [21]4 years ago
5 0
"<span>4 Na + O2  2 Na2O" is the one chemical equation among the following choices given in the question that </span><span>is correctly balanced. The correct option among all the options that are given in the question is the fourth option or option "4". I hope that this is the answer that has actually come to your great help.</span>
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The effusion rate of H2 molecules is 4.342 times that of an unknown gas. Determine the molar mass of the unknown gas.
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The effusion rate of H2 molecules is 4.342 times that of an unknown gas. Determine the molar mass of the unknown gas. You can write the formula for Graham's law of diffusion or effusion of gases as: rate 1 / rate 2 = √ (mass 2 / mass 1) , where: rate 1 and rate 2 - Rates of effusion or diffusion of Gas 1 and 2, respectively, measured moles per unit time

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1 year ago
Calculate the energy of attraction between a cation with a valence of 1 and an anion with a valence of 3 the centers of which ar
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Answer:

The energy of attraction between the cation and anion is 1.231 X 10⁻¹¹ J

Explanation:

Let the charge on the cation be q₁

Also let the charge on the anion be q₂

A cation q₁ with a valence of 1, has a charge of 1 X 1.602×10⁻¹⁹C = 1.602×10⁻¹⁹C

An anion q₂ with a valence of 3, has a charge of 3 X 1.602×10⁻¹⁹C = 4.806 ×10⁻¹⁹C

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Energy of attraction = \frac{Kq_1q_2}{r^2}

Where k is coulomb's constant = 8.99 X 10⁹ Nm₂/C₂

Energy of attraction = \frac{8.99 X 10^9 (1.602X10^{-19})(4.806 X10^{-19})}{(7.5X10^{-9})^2}

Energy of attraction = 1.231 X 10⁻¹¹ J

Therefore, the energy of attraction between the cation and anion is 1.231 X 10⁻¹¹ J

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