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lina2011 [118]
3 years ago
15

Is a saving a variable or fixed expense

Mathematics
1 answer:
ladessa [460]3 years ago
7 0

Answer:

fixed

Step-by-step explanation:

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Distribute a negative -(5.5q+7)
Ipatiy [6.2K]

Hi there! :)

Answer:

\huge\boxed{-5.5q - 7}

-(5.5q + 7)

Distribute:

-(5.5q) -(7)

-5.5q - 7

7 0
3 years ago
Read 2 more answers
the height h(t) of a trianle is increasing at 2.5 cm/min, while it's area A(t) is also increasing at 4.7 cm2/min. at what rate i
nekit [7.7K]

Answer:

The base of the triangle decreases at a rate of 2.262 centimeters per minute.

Step-by-step explanation:

From Geometry we understand that area of triangle is determined by the following expression:

A = \frac{1}{2}\cdot b\cdot h (Eq. 1)

Where:

A - Area of the triangle, measured in square centimeters.

b - Base of the triangle, measured in centimeters.

h - Height of the triangle, measured in centimeters.

By Differential Calculus we deduce an expression for the rate of change of the area in time:

\frac{dA}{dt} = \frac{1}{2}\cdot \frac{db}{dt}\cdot h + \frac{1}{2}\cdot b \cdot \frac{dh}{dt} (Eq. 2)

Where:

\frac{dA}{dt} - Rate of change of area in time, measured in square centimeters per minute.

\frac{db}{dt} - Rate of change of base in time, measured in centimeters per minute.

\frac{dh}{dt} - Rate of change of height in time, measured in centimeters per minute.

Now we clear the rate of change of base in time within (Eq, 2):

\frac{1}{2}\cdot\frac{db}{dt}\cdot h =  \frac{dA}{dt}-\frac{1}{2}\cdot b\cdot \frac{dh}{dt}

\frac{db}{dt} = \frac{2}{h}\cdot \frac{dA}{dt} -\frac{b}{h}\cdot \frac{dh}{dt} (Eq. 3)

The base of the triangle can be found clearing respective variable within (Eq. 1):

b = \frac{2\cdot A}{h}

If we know that A = 130\,cm^{2}, h = 15\,cm, \frac{dh}{dt} = 2.5\,\frac{cm}{min} and \frac{dA}{dt} = 4.7\,\frac{cm^{2}}{min}, the rate of change of the base of the triangle in time is:

b = \frac{2\cdot (130\,cm^{2})}{15\,cm}

b = 17.333\,cm

\frac{db}{dt} = \left(\frac{2}{15\,cm}\right)\cdot \left(4.7\,\frac{cm^{2}}{min} \right) -\left(\frac{17.333\,cm}{15\,cm} \right)\cdot \left(2.5\,\frac{cm}{min} \right)

\frac{db}{dt} = -2.262\,\frac{cm}{min}

The base of the triangle decreases at a rate of 2.262 centimeters per minute.

6 0
3 years ago
The diameter of the earth
Roman55 [17]

Answer:

25,132.74 miles

Step-by-step explanation:

Hello!

We are basically asked to find the circumference of the Earth's cross-section.

Circumference: C = 2\pi r

We can replace 2r with the diameter, because the diameter is 2 times the radius.

Multiply the Diameter by pi:

  • C = \pi D
  • C = 8000\pi
  • C = 25,132.7412287183  \approx 25,132.74

It is around 25,132.74 miles around.

6 0
2 years ago
HELP PLSSS THIS IS HARD SOMEONE
Stolb23 [73]

Answer:

D

Step-by-step explanation:

Just go 4 units left for the x value and 2 units up for the y value

5 0
2 years ago
Simplify the expression. 6(6) + 6(4)<br> a. 60<br> b. 10<br> c. 16<br> d. 12
olya-2409 [2.1K]
6 x 6 = 36
6 x 4 = 24
36 + 24 = 60
A
8 0
3 years ago
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