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Alekssandra [29.7K]

3 years ago

9

Write an equation in slope-intercept form for the line that satisfies the following condition. slope 6, and passes through (5, 2

0)

2 answers:

evablogger [386]3 years ago

4 0

I can't remember if this is correct or not but I believe it would be 5 multiplied by 20 plus 6. As I said I don't Know for sure if this is correct or not. However, I hope it help

EastWind [94]3 years ago

4 0

First you graph..

Start at (5,20)

Count 6 up 1 to the right three or four times then Count 6 down and 1 to the left.

You will get the y-intercept out of this...

Which is -10.

You can put it into slope-intercept form now-

y=mx+b

"m" being slope and "b" being the y-intercept.

Final Answer: y=6x+10

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Jlenok [28]

Answer:

the area of this shape equals 247.75

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3 years ago

Troista Mobile Accessories sells mobile apps on their Web site. If a customer spends on average, $12 per visit and visits the We

Leno4ka [110]

Answer: The required average is $576.

Step-by-step explanation:

Since we have given that

Percent of customers not returning each year = 25%

Average customer lifetime = $\dfrac{1}{0.25}=4\ years$

Percent of margin on the average bill = 60%

Cost per visit = $12

Number of times each year visited = 20 times

So, Average expense by each customer per year = $12\times 20=\$240$

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Average non discounted gross profit during a customer's lifetime is given by

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Hence, the required average is $576.

8 0

4 years ago

A rectangular garden of area 208 square feet is to be surrounded on three sides by a brick wall costing $ 8 per foot and on one

vova2212 [387]

Answer:

Therefore the dimensions of the garden is 16 feet by 13 feet.

Step-by-step explanation:

Let the length of the garden be x and the width of the garden be y.

Given that the area of the rectangular garden is 208 square feet.

Therefore,

xy =208

$\Rightarrow y = \frac{208}{x}$

Again given that,

The garden is to be surrounded on three sides by a brick wall costing $ 8 per feet and the remaining sides by a fence costing $5 per feet.

The perimeter of the rectangle is = 2(length+ breadth)

= 2(x+y)

=2x+2y

The total cost of fence

$C= [ (2x\times 8)+(y\times 8)+(y\times 5)]$

= (16x+ 8y +5y)

$=16x+13y$

$=16x+\frac{13\times 208}{x}$

$=16x +\frac{2704}{x}$

To find the maximum or minimum point, we need to find out $\frac{dC}{dx}$ and set $\frac{dC}{dx}$ =0.

$\frac{dC}{dx}=16 -\frac{2704}{x^2}$

Then

$16 -\frac{2704}{x^2}=0$

$\Rightarrow \frac{2704}{x^2}=16$

$\Rightarrow x^2 =\frac{2704}{16}$

$\Rightarrow x=\pm \sqrt{169}$

$\Rightarrow x=\pm 13$

Again $\frac{d^2C}{dx}= \frac {8112}{x^3}$

$\therefore\left| \frac{d^2C}{dx}\right |_{x=13}= \frac {8112}{13^3}>0$

Therefore at x= 13 , the cost is minimum.

Therefore x = 13 feet.

The other side of the garden is $=\frac{208}{13}$ feet = 16 feet.

Therefore the dimensions of the garden is 16 feet by 13 feet.

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Kay [80]

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3 years ago

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