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Alekssandra [29.7K]
3 years ago
9

Write an equation in slope-intercept form for the line that satisfies the following condition. slope 6, and passes through (5, 2

0)
Mathematics
2 answers:
evablogger [386]3 years ago
4 0
I can't remember if this is correct or not but I believe it would be 5 multiplied by 20 plus 6. As I said I don't Know for sure if this is correct or not. However, I hope it help
EastWind [94]3 years ago
4 0
First you graph..


Start at (5,20)


Count 6 up 1 to the right three or four times then Count 6 down and 1 to the left.

You will get the y-intercept out of this...

Which is -10.

You can put it into slope-intercept form now-

y=mx+b

"m" being slope and "b" being the y-intercept.

Final Answer: y=6x+10
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a company declared a dividend of $1.50 per share. john has 600 shares in the company. how much will she get?​
Harman [31]

Answer:

$900

Step-by-step explanation:

So if each individual share is $1.50 we can presume that we need to multiply both factors. 1 x 600 is 600 and .50 x 600 is 300. 600 + 300 = 900. John will get $900 in shares profit.

3 0
3 years ago
What should you do to solve the equation? 45 = x + 38
antoniya [11.8K]

All you have to do is subtract 38 from 45 to get 7 as your answer.

8 0
3 years ago
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Price per volleyball if 6 volleyballs cost $18.00? Please I need helpppp
Nastasia [14]

Answer:

The price per volleyball is $3.

Step-by-step explanation:

Divide $18 by 6 for the cost of each volleyball in which your final answer should be $3 per volleyball.

7 0
3 years ago
What is the outlier in the following data set:<br> 15,11,10,8,9,1,8,7,5,4,2,3, and 37?
NeTakaya

Step-by-step explanation:

The steps to find an outlier:

1. Put the data in numerical order.

2. Find the median.

3. Find the medians for the top and bottom parts of the data. This divides the data into 4 equal parts.

The median with the smallest value is called Q1. The median for all the values - usually just called the median is also called Q2. The median with the largest value is Q3.

4. Subtract...Q3 - Q1. This value is the InterQuartileRange or IQR. Remember that the range means taking the largest minus the smallest. This is a special range having to do with the quartiles.

5. Multiply...1.5 * IQR

6. Take your answer from #5 and do 2 things with it. A). Subtract it from Q1 and B) Additional to Q3.

7. Look at all your data points. If any are SMALLER than Q1 - 1.5 *IQR, they are outliers. If any are LARGER than Q3 + 1.5 *IQR, they are also outliers.

For your data....the median, Q2 is

(43+38)/2 = 40.5.

Q1 = (30+26)/2 = 28.

Q3 = (54+52)/2 = 53

The IQR is 53 - 28 = 25

1.5 * IQR = 37.5

Q1 - 37.5 = 28 - 37.5 = -9.5. There is no data value less than -9.5.

Q3 + 37.5 = 53 + 37.5 = 90.5. there is no data value greater than 90.5.

My conclusion is that there are no outliers in this data.

I hope this helps!

4 0
3 years ago
The base of a prism is a right triangle with a base and height measurement of 12cm and a 5cm. If the volume of the prism is 210c
bezimeni [28]

Answer:

The height is 7 cm

Step-by-step explanation:

210 × 2 = 420

12 × 5 = 60

420 ÷ 60 = 7

6 0
4 years ago
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