The correct question is
<span>A student ate 3/20 of all candies and another 1.2 lb. Another student ate 3/5 of the candies and the remaining 0.3 lb. Altogether, what weight of candies did they eat?</span>
let
x-------> total <span>weight of candies
we know that
x=(3/20)*x+1.2+(3/5)*x+0.3
</span>x=(3/20)*x+(3/5)*x+1.5----> multiply by 20----> 20x=3x+12x+30
20x=15x+30
20x-15x=30
5x=30
x=6 lb
the answer is
6 lb
nt / (n+t)
substitute n=15 and t=7
(15*7)/(15+7)
105/22
22 goes into 105 4 times with 17 left over
4 17 /22
1.) -15.9, -15.2, -3.6, 3.6
2.) second one is already correct
3.)-2.3, -2.03, 2.03, 3.0
A) a1=0 a2=9
b)m1=0 m2=5
c)r1=0 r2=1.25 or 5/4
Answer:
The second option.
Step-by-step explanation: