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joja [24]
3 years ago
15

A student ate 3/20 of all candies and another 1.2 lb. Another student ate 35 of the candies and the remaining 0.3 lb. Altogether

, what weight of candies did they eat?
Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
8 0
The correct question is
<span>A student ate 3/20 of all candies and another 1.2 lb. Another student ate 3/5 of the candies and the remaining 0.3 lb. Altogether, what weight of candies did they eat?</span>

let
x-------> total <span>weight of candies
we know that

x=(3/20)*x+1.2+(3/5)*x+0.3
</span>x=(3/20)*x+(3/5)*x+1.5----> multiply by 20----> 20x=3x+12x+30
20x=15x+30
20x-15x=30
5x=30
x=6 lb

the answer is
6 lb
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Zoe had 3 1 /8 feet of orange ribbon. She used some ribbon to make a bow for a gift now she has 1 3 /8 feet of orange ribbon lef
Nastasia [14]

Answer:

Orange ribbon Zoe use is  1\frac{3}{4} \ feet.

Step-by-step explanation:

Given:

Zoe had 3 1 /8 feet of orange ribbon. She used some ribbon to make a bow for a gift now she has 1 3 /8 feet of orange ribbon left.

Now, to find the orange ribbon Zoe use.

Let the orange ribbon Zoe use be x.

Total orange ribbon Zoe had = 3\frac{1}{8} = \frac{25}{8} \ feet.

Ribbon Zoe had left = 1\frac{3}{8} =\frac{11}{8} \ feet.

Now, to get the orange ribbon Zoe use:

\frac{25}{8} -x=\frac{11}{8}

<em>Subtracting both sides by </em>\frac{11}{8}<em> we get:</em>

\frac{25}{8} -x-\frac{11}{8} =0

<em>Adding both sides by </em>x<em> we get:</em>

\frac{25}{8} -\frac{11}{8} =x

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x=\frac{14}{8}

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x=1\frac{3}{4}\ feet.

Therefore, orange ribbon Zoe use is 1\frac{3}{4} \ feet.

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