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Xelga [282]
3 years ago
14

An animal shelter has 5 times as many cats as it has dogs. There are 75 cats at the shelter. If d= the number of dogs, which mat

hematical sentence expresses the information above? A. 5d=75 B. d/5=75 C. d/75=5 D. 75d=5
Mathematics
2 answers:
KiRa [710]3 years ago
7 0

Answer:

<h2>A. 5D=75</h2>

Step-by-step explanation:

To solve this problem, we have to translate this to equations.

<h3>5 times as many cats as it has dogs:</h3>

C=5D

That is, there are 5 times more cats than dogs, or the number of cats is five times than the number of dogs.

<h3>There are 75 cats.</h3>

C=75

<h3>Therefore, the expression would be</h3>

75=5D \ or \ 5D=75

Cerrena [4.2K]3 years ago
3 0
A. 5d=75
5 cats = 1 dog; 75 cats = d





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Casey Bought 6 bags of chips

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If each sandwich costs 3 times the amount of a bag of chips and the sandwich is 6 dollars, the chips are 2 dollars. Casey bought 5 sandwiches and spent $30 dollars on sandwiches. Since the total was $42 dollars you have $12 dollars left to get your total of $42. 2x6 = 12 so therefore Casey bought 6 bags of chips.

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At an effective annual interest rate of i &gt; 0, each of the following two sets of payments has present value K: (i) A payment
IgorLugansk [536]

Answer:

The present value of K is, K=251.35

Step-by-step explanation:

Hi

First of all, we need to construct an equation system, so

(1)K=\frac{169}{(1+i)} +\frac{169}{(1+i)^{2}}

(2)K=\frac{225}{(1+i)^{2}} +\frac{225}{(1+i)^{4}}

Then we equalize both of them so we can find i

(3)\frac{169}{(1+i)} +\frac{169}{(1+i)^{2}}=\frac{225}{(1+i)^{2}} +\frac{225}{(1+i)^{4}}

To solve it we can multiply (3)*(1+i)^{4} to obtain (1+i)^{4}*(\frac{169}{(1+i)} +\frac{169}{(1+i)^{2}}=\frac{225}{(1+i)^{2}} +\frac{225}{(1+i)^{4}}), then we have 225(1+i)^{2}+225=169(1+i)^{3}+169(1+i)^{2}.

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Finally, we replace it in (1) or (2), let's do it in (1) K=\frac{169}{(1+0.2224)} +\frac{169}{(1+0.2224)^{2}}\\\\K=251.35

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3 years ago
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