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3 years ago

kylie bought a bunch of grapes that weighs 2 pounds and 9 ounces. How much did the grapes weigh in ounces only?

1 answer:

7 0

Since 1 pound is 16 ounces, you would convert the 2 pounds to 32 ounces (16+16) and add the 32 ounces to the already given 9 ounces to get 41 ounces. (32+9)
Hope that helped.

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Mean and median height: An association of U.S. dog breeders reported in a recent year that the mean height for their adult dogs

Ray Of Light [21]

Answer:

We should expect the histogram to be skewed to the right.

Step-by-step explanation:

The median separates the upper half from the lower half of a set. So 50% of the values in a data set lie at or below the median, and 50% lie at or above the median.

The mean is the average of all the values in the set.

Median, mean and skewness of the histogram:

If the mean is greater than the median, the histogram has positive skewness, that is, it is skewed to the right.

If the mean is lesser than the median, the histogram has negative skewness, that is, it is skewed to the left.

If the mean and the median are equal, the histogram is approximately symmetric.

In this problem, we have that:

Mean = 22

Median = 15.9

So we should expect the histogram to be skewed to the right.

7 0

3 years ago

Given the tables for f & g below, find the following: x f ( x ) g ( x ) 0 9 7 1 4 8 2 3 6 3 5 1 4 7 5 5 1 2 6 6 0 7 0 4 8 2

d1i1m1o1n [39]

$\\(i)\\
\text{We know that the average rate of change of a function f(x) on inerval [a,b] is}\\
\\
f_{avg}=\frac{f(b)-f(a)}{b-a}\\
\\
\text{so using this the average rate of chang of g for x on interval }[3,7] \text{ is}\\
\\
g_{avg}=\frac{g(7)-g(3)}{7-3}\\
\\
=\frac{4-1}{4}\\
\\
=\frac{3}{4}\\
\\
\text{so average rate of change of g on interval [3,7] is }\frac{3}{4}$

$\\(ii)\\ \text{Average rate of chang of f for x on interval }[3,7] \text{ is}\\
\\
f_{avg}=\frac{f(7)-f(3)}{7-3}\\
\\
=\frac{0-5}{4}\\
\\
=\frac{-5}{4}\\
\\
\text{so average rate of change of g on interval [3,7] is }\frac{-5}{4}$

$\\(iii)\\
\text{Since g(4)=5, so we have}\\
\\
f(g(4))=f(5)\\
\\
\text{since the value of f is 1 at x=5. so }\\
\\
f(g(4))=f(5)=1\\
\\
\text{hence we have, }f(g(4))=$ 1

$\\(iv)\\
\text{Since f(3)=5, so we have}\\
\\
g(f(3))=g(5)\\
\\
\text{since the value of g is 2 at x=5. so }\\
\\
g(f(3))=g(5)=2\\
\\
\text{hence we have, }g(f(3))=$ 2

5 0

3 years ago

How do you simply 3(x+3)-2x

kiruha [24]

3(x+3)-2x
Distribute the 3
3x+9-2x
Combine like terms
x+9
Set equal to zero if you need to do this part
x+9=0
Get x by itself
x=-9

8 0

3 years ago

10) Jacolby can score 30 goals in 6 minutes. Khamari can score 42 goals in 7 minutes. How many more goals can Khamari make per m

lidiya [134]

Answer:

c)1 goal

Step-by-step explanation:

Since Jacolby can make 30 goals in 6 minutes, that makes (30/6) 5 goals per minute. Khamari can make 42 goals in 7 minutes, that makes (42/7) 6 goals per minute. So Jalcolby is 5 and Khamari is 6, and the question is asking how many MORE. 6-5 is 1, so Khamari can make 1 more goal per minute than Jacolby.

Hope this helps.

6 0

3 years ago

Find tan of 45 degrees

Arturiano [62]

Answer:

tan(45°) = 1

Step-by-step explanation:

We know that sin (45°) = √2/2, and cos(45°) = √2/2.

Given that tan(x) = sen(x) / cos(x), we get:

tan(45°) = (√2/2) / (√2/2) = 1

Therefore, tan(45°) = 1

Attached you will find the important angles summary

6 0

3 years ago