Answer:
Step-by-step explanation:
Let's call hens h and ducks d. The first algebraic equation says that 6 hens (6h) plus (+) 1 duck (1d) cost (=) 40.
The second algebraic equations says that 4 hens (4h) plus (+) 3 ducks (3d) cost (=) 36.
The system is
6h + 1d = 40
4h + 3d = 36
The best way to go about this is to solve it by substitution since we have a 1d in the first equation. We will solve that equation for d since that makes the most sense algebraically. Doing that,
1d = 40 - 6h.
Now that we know what d equals, we can sub it into the second equation where we see a d. In order,
4h + 3d = 36 becomes
4h + 3(40 - 6h) = 36 and then simplify. By substituting into the second equation we eliminated one of the variables. You can only have 1 unknown in a single equation, and now we do!
4h + 120 - 18h = 36 and
-14h = -84 so
h = 6.
That means that each hen costs $6. Since the cost of a duck is found in the bold print equation above, we will sub in a 6 for h to solve for d:
1d = 40 - 6(6) and
d = 40 - 36 so
d = 4.
That means that each duck costs $4.
<em>x = - 9</em>
- Step-by-step explanation:
<em>6x + 10 = 4x - 8</em>
<em>6x - 4x = - 10 - 8</em>
<em>2x = - 18</em>
<em>x = - 18 : 2</em>
<em>x = - 9</em>
Answer:
How are we supposed to know .???
we can only see half of the problem
Step-by-step explanation:
Answer:
A. 
Step-by-step explanation:
The third order polynomial is factored herein:
Which represents answer A.
1) Diameter = Line MN, Chord = Line LN
<span>2) B --- GFC </span>
<span>3) C --- GCE </span>
