Answer:
The amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.
Step-by-step explanation:
Consider the provided information.
A chemical flows into a storage tank at a rate of (180+3t) liters per minute,
Let
is the amount of chemical in the take at <em>t </em>time.
Now find the rate of change of chemical flow during the first 20 minutes.

![\int\limits^{20}_{0} {c'(t)} \, dt =\left[180t+\dfrac{3}{2}t^2\right]^{20}_0](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%7B20%7D_%7B0%7D%20%7Bc%27%28t%29%7D%20%5C%2C%20dt%20%3D%5Cleft%5B180t%2B%5Cdfrac%7B3%7D%7B2%7Dt%5E2%5Cright%5D%5E%7B20%7D_0)


So, the amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.
Answer:
1/3(n - 5) = -2/3
distribute 1/3
3
Step-by-step explanation:
I got it correct on edgen
A, using the formula length= Area: width
and we have the length= 3535:2525= 1,4 m or this number as a fraction 14/10=7/5
But the length is smaller than the width?
b, I think you type wrongly the problem
The other person is literally wrong. The answer is D. Supplementary because two angles that add up to 180 are supplementary angles.
Answer:
A= -1
Step-by-step explanation: