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3 years ago

If x^ 3 = -27, then what is x?

Mathematics

2 answers:

wariber [46]3 years ago

7 0

The cube root of -27 is -3

3√-27 = -3

You can check this by plugging your answer back it

X= -3

-3^3 = -27

LekaFEV [45]3 years ago

6 0

Take 3rd root of -27
that is -3

if you can't see it then
√-27=(√-1)(√27)=(-1)(3)=-3

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How many terms are in the polynomial abcd + e - h27 O two O three O five O six

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4 years ago

Write an equation in slope intercept form for a line perpendicular to the line

konstantin123 [22]

Answer:

y=(1/3)x- 4/3

Step-by-step explanation:

If two lines are perpendicular to each other, then the slopes will be the negative inverse to each other.

Example:

the negative inverse of 2 is -1/2

the slope of $y=-3x+2$ is -3

the negative inverse of -3 is $\dfrac{1}{3}$

So we have the perpendicular line be : $y=\dfrac{1}{3}x+b$

Since it also go through (4,0)

plug in we get $0 = \dfrac{4}{3}+b$

$b=-\frac{4}{3}$

So the equation would be

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3 years ago

If [infinity] cn8n n = 0 is convergent, can we conclude that each of the following series is convergent? (a) [infinity] cn(−3)n

pashok25 [27]

Answer:

a) we know that this is convergent.

b) we know that this might not converge.

Step-by-step explanation:

Given the $\sum^\infty_{n=0}C_n8^n$ is convergent

Therefore,

(a) $\sum^\infty_{n=0}C_n(-3)^n$ The power series $\sum C_nx^n$ has radius of convergence at least as big as 8. So we definitely know it converges for all x satisfying -8<x≤8. In particular for x = -3

∴ $\sum^\infty_{n=0}C_n(-3)^n$ is convergent.

(b) $\sum^\infty_{n=0}C_n(-8)^n$ -8 could be right on the edge of the interval of convergence, and so might not converge

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3 years ago