1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Leto [7]
3 years ago
5

If x^ 3 = -27, then what is x?

Mathematics
2 answers:
wariber [46]3 years ago
7 0
The cube root of -27 is -3

3√-27 = -3

You can check this by plugging your answer back it

X= -3

-3^3 = -27
LekaFEV [45]3 years ago
6 0
Take 3rd root of -27
that is -3

if you can't see it then
√-27=(√-1)(√27)=(-1)(3)=-3
You might be interested in
Help me to do this math question ​
viva [34]

Answer:

b) q

c) 7a

d) 2y

Step-by-step explanation:

b) q must be added to p to get p+q

c) 12a-7a = 5a

d) 2y is subtracted from 3x

5 0
3 years ago
Read 2 more answers
Laila read 36 pages in 4 hours. Which expression can be used to find the number of pages she read per hour?
klio [65]

Answer:

36 pages/4 hours

Step-by-step explanation:

The answer is 36 pages/4 hours

3 0
3 years ago
Read 2 more answers
A consumer purchase a computer after a 20% price reduction. If x represent the computer’s original price, the reduced price can
Musya8 [376]

Answer:

.80x

Step-by-step explanation:

If the price is reduced by 20% we are paying 100-20 or 80 percent

The new price is

x* 80%

.80x

7 0
3 years ago
I keep putting in the formula but I keep getting the answer wrong​
Advocard [28]

Answer:

314 in²  (nearest whole number)

Step-by-step explanation:

<u>Radius of a regular polygon</u>: The distance from the <u>center</u> of the polygon to any vertex.  The radius of a hexagon is equal to the length of one side.

Therefore, from inspection of the given diagram:

  • radius = 11 in  ⇒  side length = 11 in

To find the area of a regular polygon, we first need to calculate the apothem.   The <u>apothem</u> is the line drawn from the center of the polygon to the midpoint of one of its sides.

\textsf{Length of apothem (a)}=\dfrac{s}{2 \tan\left(\frac{180^{\circ}}{n}\right)}

where:

  • s = length of one side
  • n = number of sides

Given:

  • s = 11 in
  • n = 6

Substitute the given values into the formula and solve for a:

\implies \textsf{a}=\dfrac{11}{2 \tan\left(\frac{180^{\circ}}{6}\right)}=\dfrac{11\sqrt{3}}{2}

<u>Area of a Regular Polygon</u>

\textsf{A}=\dfrac{n\:s\:a}{2}

where:

  • n = number of sides
  • s = length of one side
  • a = apothem

Given:

  • n = 6
  • s = 11
  • \textsf{a}=\dfrac{11\sqrt{3}}{2}

Substitute the given values into the formula and solve for A:

\implies \sf A=\dfrac{6 \cdot 11 \cdot \dfrac{11\sqrt{3}}{2}}{2}

\implies \sf A=314.3672216...

\implies \sf A=314\:\:in^2\:\:(nearest\:whole\:number)

8 0
2 years ago
a regular square pyramid just fits inside a cube (the base of the pyramid is congruent to a face of the cube and the height of t
Tom [10]
The answer is larger in volume because the come is holow in the inside and that square pyrimid isn't
3 0
3 years ago
Other questions:
  • Each base of a triangular prism is a right triangle with side lengths 3 inches, 4 inches, and 5 inches. The height of the prism
    11·1 answer
  • I have 7 cowry shells. If a dozen eggs (12 eggs) cost 3 cowry shells, how many dozens can I purchase?
    6·1 answer
  • Which is the simplified form of x Superscript negative 12?
    5·2 answers
  • Estimate to check for reasonables. 306×21​
    9·1 answer
  • Simply each expression by combining like<br> terms. -7W + 2W - 12W-W
    15·1 answer
  • a.When the numerator and the denominator have no common factor other than 1; he fraction is either a proper fraction or mixed nu
    6·1 answer
  • What is the square root of 243 reduced?
    13·1 answer
  • Help Pls ima fail school lol
    8·1 answer
  • Solve the answer <br> 6p - 1 - 4p = 15?
    12·1 answer
  • Find the area of a triangle whose base is 10 mm, and its height is 15 mm.
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!