The ellipse 14x2+2x+y2=114x2+2x+y2=1 has its center at the point (b,c)(b,c) where
1 answer:
18x^2 + 2x + y^2 = 1
<span>==> 18(x^2 + x/9) + y^2 = 1 </span>
<span>==> 18(x^2 + x/9 + 1/324) + y^2 = 1 + 1/18 </span>
<span>==> 18(x + 1/18)^2 + y^2 = 19/18 </span>
<span>==> (x + 1/18)^2/19 + (y - 0)^2/(19/18) = 1. </span>
<span>By comparing this to the standard form of an ellipse, the center is at (-1/18, 0). </span>
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Step-by-step explanation:
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Step-by-step explanation:
2*-2=-4
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a = (8 – 5)
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Using the standard form:
(x – h)^2 = 4a(y – k)
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In general form
x^2 -10x +25 =12y – 48
x^2 -10x -12y + 73 =0
